Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- Problem 3. Strains are measured on the surface of a structural component as &A = = 1200 x 10-6. EB = 500 x 10-6, &c = 300 × 10-6. E = 200 GPa and v = 0.3. b) a) Find the principal stresses and show these on a sketch of a properly oriented element. Use Mohr's Circle to find the stresses at 0 = 30° counterclockwise from the x axis and show these on a sketch of a properly oriented element. y 60° C B A Xarrow_forward20 (B) An air vessel, which is made of steel in 2 m long. It has an external diameter 44 cm and is 2 cm thick. 1. Calculate the permissible pressure difference allowed between the inside and outside if the longitudinal stress in the wall must not exceed 20 MPa. 2. Determine longitudinal and hoop strains. 3. Calculate the change in diameter and change in volume. Take E = 200 GPa and v = 0.3arrow_forwardFigure 2 shows a bar with a length L fixed at the left end. Question 2 The uniformly distributed force f (unit: N/m) is applied along the axis of the bar, and a concentrated force P (unit: N) is applied at the free end of the bar. The bar has a constant Young's modulus E and cross-section area A. Find the stretch of the bar: (a). at the free end of the bar; (b). at the center of the bar. (Expressing all the resulta with E, A, L, f, and P). E, A L Fig. 2. The kft end of the bar is fd, ad the froe ed of the bar is applied with a force P. The uniformly distribatod kece f is applied akong the ais of the bar.arrow_forward
- 1cm t1 (cm) P 3,2 cm t2 (cm) t1 (cm) 1 cm 20 cm Ь (ст) P = 20t %3D Dp=1,6 cmarrow_forward4. A solid shaft was made of alloy steel, it was welded to a flat plate by a specific size of fillet weld. If a torque is applied to the shaft, calculate the size of the weld joint. Power Torque Yield stress Shear stress Ultimate stress (Mpa) Compression stress (Mpa) Ductility (%) (kw) (Nm) 1000 (Mpa) 400 (Mpa) 160 280 30 Modulus of Bending Stress Bending Moment Factor of Safety Elasticity (GPa) (Mpa) 220 280 120 4 Modulus of Rigidity (pa) 70 Fracture stress (Mpa) 250arrow_forwardQ.5) A bar of 1000 mm length and 40 mm diameter is centrally bored for 300 mm length at one end at a diameter of 20 mm. Young's modulus of the material is 2 x 10° N/mm². If the bar is 2 40 mm 20 mm 700 mm 300 mm loaded axially with a load of 30 kN the extension produced is (A) 0.1136 mm (C) 0.1478 mm (B) 0.1313 mm (D) 0.1542 mmarrow_forward
- AL: 1₂ The above figure (not drawn to scale) shows a rod made up of two cylindrical sections of the same material. The left cylinder has diameter d, = 30mm and length 4 = 150mm. The right cylinder has diameter dy=10mm and length = 150mm. The rod is subjected to a force F = 50KN. Find the total extension in the rod, AL, given that E = 203kN/mm². Enter your answer in mm to 5 decimal places in the box below: mm -Farrow_forwardQUESTION 2 1.2 A thin cylindrical pressure vessel has the following specifications Internal pressure 5.33 MPa Metal thickness 20 mm Maximum allowable stress 120 MPa Efficiency of the longitudinal joint Efficiency of the circumferential joint 80 % 50 % 1.21 Determine the maximum internal diameter which the cylinder may have. 1.2.2 The actual values of the hoop and longitudinal stresses. For the soolbar, press ALT=P10 (PC) or ALT-FN-F10 (Mac). B IUS Paragraph Ara !! 140x AITZAN LAINAarrow_forward
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