need too much urgent 1.The one line diagram of a four bus system is shown in the figure below. All the line impedances(in per unit) are given in the diagram.0.05 +j 0.15-0.15 + j 0.4530.05 +j 0.154Figure for question 1The specified quantities at the buses are tabulated below:BusRemarksQIVI1Swing10°Generator0.251---Load-1.00.8---4Load0.3-0.2(a) Prepare the bus admittance matrix of the system shown in the above figure.(b) Find the unknown quantities of each bus at the end of 2nd iteration using Gauss-Seidel Method.0.1 +j 0.30.1 +j 0.3

In power systems analysis, the Y-bus (also known as admittance matrix or admittance bus matrix) is a…

1. The one line diagram of a four bus system is shown in the figure below. All the line impedances (in per unit) are given in the diagram. Figure for question 1 The specified quantities at the buses are tabulated below: Bus 1 2 3 0.05 +j 0.15 A -0.15+j 0.45 0.15+J 0.05 +j0.15 4 Remarks Swing Generator Load Load P 0.25 -1.0 0.3 0.8 -0.2 |VI 1 1 (a) Prepare the bus admittance matrix of the system shown in the above figure. 8 0⁰

1. The one line diagram of a four bus system is shown in the figure below. All the line impedances (in per unit) are given in the diagram. Figure for question 1 The specified quantities at the buses are tabulated below: Bus 1 2 3 0.05 +j 0.15 A -0.15+j 0.45 0.15+J 0.05 +j0.15 4 Remarks Swing Generator Load Load P 0.25 -1.0 0.3 0.8 -0.2 |VI 1 1 (a) Prepare the bus admittance matrix of the system shown in the above figure. 8 0⁰

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter9: Unsymmetrical Faults

Section: Chapter Questions

Problem 9.55P

See similar textbooks

Similar questions

Problem 5 Consider the system shown in the single-line diagram of Figure (3). All reactances are shown in per unit to the same base. Assume that the voltage at both sources is 1 p.u. a- Find the fault current due to a bolted- three-phase short circuit at bus 3. b- Find the fault current supplied by each generator and the voltage at each of the buses I and 2 under fault conditions. 0.04 p.u. 0.2 p.u. 0.06 p.u. 0.2 p.u. 0.25 p.u. G, 0.2 p.u. 0.2 p.u. 0.06 p.u. 0.06 р.и. 3 0.25 p.u. 0.25 p.u. G, Figure (3) Single-line diagram for Problem 5 ele
Consider the system shown in the single-line diagram of Figure (3). All reactances are shown in per unit to the same base. Assume that the voltage at both sources is 1 p.u. a Find the fault current due to a bolted- three-phase short circuit at bus 3 b- Find the fault current supplied by each generator and the voltage at each of the buses 1 and 2 under fault conditions 0.06 p.u. 0.2 p.u. 0.04 p.u. 0.25 p.u. 0.2 p.u. 0.2 p.. 0.2 p.u. 0.06 p.u. 0.25 p.u. Figure (3) Single-line diagram ele ver ele 888 ele 0.06 p.u. 0.25 p.u.
1. FIGURE 52 shows the one-line diagram of a simple three-bus power system with generation at bus I. The voltage at bus l is V1 = 1.0L0° per unit. The scheduled loads on buses 2 and 3 are marked on the diagram. Line impedances are marked in per unit on a 100 MVA base. For the purpose of hand calculations, line resistances and line charging susceptances are neglected a) Using Gauss-Seidel method and initial estimates of Va 0)-1.0+)0 and V o)- ( 1.0 +j0, determine V2 and V3. Perform two iterations (b) If after several iterations the bus voltages converge to V20.90-j0.10 pu 0.95-70.05 pu determine the line flows and line losses and the slack bus real and reactive power. 2 400 MW 320 Mvar Slack 0.0125 0.05 300 MW 270 Mvar FIGURE 52
QUESTION 3 The power system network is shown in Figure 3. The magnitude of voltage at bus 1 is adjusted to 12 0° per unit, buses 2 and 3 are the load buses. Line impedances are marked in per-unit on 100 MVA base and the charging susceptances are neglected. Determine the bus voltage at load 2 and 3 using the Gauss-Seidel iteration method (accurate to four decimal places). Perform calculation for two iterations. jo.033 P= 400 Mw HQu= 320 MVar Vi = 120° Figure 3 10.05 +P= 300 MW 70.0125 +QF 270 MVar
Q2. Figure Q2 shows a 300 MW, 50 Hz generator transmitting 280 MW real power to an infinite bus through double transmission lines. A three-phase fault occurs at point P in the middle of one of the transmission lines. (i) Write the generator output power-angle equation per unit for pre-fault, during fault and post-fault conditions. (ii) Determine the critical clearing angle using equal criteria method E=1.05 p.u X'=j0.12 p.u X=j0.17 p.u @ Figure Q2 Xime=j0.6 p." Xime=j0.6 p.u P * V=1.0 p.u
In a 7-bus system, the double line fault is occurred at bus -5. During fault the positive sequence potential difference between the bus-4 and bus-1is found to be 0.0175. what is the line impedance which is connected between bus-4 and bus-1 if the current flowing through transmission line is -j 0.148? Select one: O a. -jo.182 O b. +j0.1182 O c. -jo.1182 O d. +j0.182
Busl UIN: Bus2 Bus3 Figure 1: One line diagram All impedances are specified in per unit. For generators, assume Z' = Z =j0.2, z° = j0.05 For transformers, assume Z*= Z =Z° = j0.05 For lines assume Z* = Z =j0.1, z° = j0.3 Assume unloaded pre-fault condition with voltages = 1.0 pu at all the three buses. A fault occurs at bus a1 Ignore phase shift and perform the following computations: Draw the sequence network diagrams (positive, negative and zero) and find the Thevenin equivalent for each sequence network at bus 1 where the fault occurs.
Q2\ The one-line diagram of a simple power system is shown in figure below. All impedances are expressed in per unit (pu) on a common MVA base. All resistances and shunt capacitances are neglected. The generators are operating on no load at their rated voltage. A three-phase fault occurs at bus 1 through a fault impedance of Zf = j0.08 per unit. Using Thevenin's theorem obtain the impedance to the point of fault and the fault current in per unit. Determine the bus voltages and line currents of generators during fault. X₁ = = 0.1 XT-0.1 3 1 to ojo XL=0.2 2 040 X₁ = 0.1
The one line diagram of a simple 3-bus power system shown below. All impedances are expresses in per unit on a common base. A three phase fault occurs at bus 3 through a fault impedance Z =j 0.19 pu, calculate the per unit fault current. A. 1.5 p.u. B.2.5 p.u. G₁ j 0.05 j0.75 j 0.3 3 C. 5.0 p.u. D. 3.0 p.u. G₂ j 0.075 j0.45 2
b) A fault occurs at bus 4 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. jX(1) j0.1Y p.u. jX2)= j0.1Y p.u. jXko) = j0.1X p.u. V₁ = 120° p.u. V₂ = 120° p.u. (i) (ii) 0 jX(1) = j0.2 p.u. 1 jx(2) j0.2 p.u. 2 jX1(0) = j0.25 p.u. jXT(1) jXT(2) 종 3 j0.1X p.u. JX3(1) j0.1Y p.u. j0.1X p.u. JX3(2) j0.1Y p.u. jXT(0) j0.1X p.u. JX3(0)=j0.15 p.u. 0 = x = 1, jX2(1) j0.2Y p.u. V₁=1/0° p.u. jX(2(2) = j0.2Y p.u. jX2(0) = j0.3X p.u. = V3 = 120° p.u. Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: y = 7 = = jXa(r) = j0.13 p.u., jXa(z) = j0.13 p. u., and jXa(o) = j0.12 p. u. Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from…
Most buses in a typical power-flow program are a.voltage controlled bus b.PQ bus c.PV bus d.Slack bus 2-The power-flow problem is the computation of voltage magnitude and phase angle at each bus in a power system under balanced three-phase steady-state conditions. False True 3-The following sequence currents were recorded in a power system under a fault condition Ipositive=j1.5pu, Inegative=–j0pu, Izero=– j0pu. The fault is a.Three-phase b.Double Line to ground c.Line to ground d.Line to line 4- he following sequence currents were recorded in a power system under a fault condition Ipositive=j1.5pu, Inegative=j0pu, Izero=j0pu. The fault is a.Three-phase b.Double Line to ground c.Line to ground d.Line to line i uploded the houndots (book )here :https://seomidea.com/hct/nu.pdf
b) A fault occurs at bus 3 of the network shown in Figure Q4. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, transformer and load are given in Figure Q4. V₁ = 120° p.u. V₂ = 120° p.u. V₂ = 1/0° p.u. V₂= 120° p.u. jXj0.1 p.u. JX2) 0.1 p.u. jX0j0.15 p.u. jXn-j0.2 p.u. 1 JX(2)-j0.2 p.u. 2 jX)=j0.25 p.u. JX20-10.15 p.u. jXa(z)-j0.2 p.u. 4 jX2(0)=j0.2 p.u. jXT(1) j0.1 p.u. jXT(2)=j0.15 p.u. jXT(0)=j0.1 p.u. Figure Q4. Circuit for problem 4b). = jXj0.1 p.u. j0.1 p.u. - JX(2) JXL(0) 10.1 p.u. = (i) Assuming a balanced excitation, draw the positive, negative and zero sequence Thévenin equivalent circuits as seen from bus 3. (ii) Determine the positive sequence fault current for the case when a three- phase-to-ground fault occurs at bus 3 of the network. (iii) Determine the short-circuit fault current for the case when a one-phase- to-ground fault occurs at bus…