1. The major drawback to a series regulated supply is inefficiency. Efficiency is defined as the percentage of input power that can be delivered to the load. For the circuit in Figure 2, assume the input power is 2.01 W (115 mA at 17.5 V). With the output set to 10 V and a 110 Q load resistance, calculate the efficiency of the regulator. 1/4 A 12.6 VAC R₁ 2.7 k C₁ 1000μF SK3024 R₂ ww 330 22 L₂ 2N3904 D,+SV Styles IN4733 R₂ 1.0 k R. 1.0 k R₂ 51.2 kΩ R₂ three 330 2

The Figure 2 shows an electronic circuit designed for supplying power to a load (R1). The supply voltage 235V (RMS, AC) at frequency of 50HZ. The required DC voltage and power for the load are 24V and 3.6 W respectively. The Electrical Components of this AC to DC converter are: A full-wave rectifier to convert AC voltage to DC voltage. A regulator with transistor and Zener diode to ensure a constant voltage and power for the load. D1 Iide 91 Vaut VLoad D2 D3 Vde VI sine R1 RL Regulate Reetifier Figure 2. Complete Circuit Assume that the diodes are real diodes (NOT ideal diodes). The following information is available: The collector to base resistor of the regulator R1 = 5.0 k The transistor Q1 with B value of 24 is used for the regulator circuit. Determine the following quantities for this electronic device and fill the table below: Question Answer The voltage of Zener Diode (Vz) The current in R1 The DC current into the regulator | (Idc) Base current of transistor (IB) Collector…

Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the above

A resistor Ra is in series with a voltage source Va. Draw the circuit. Label the voltage across the combination as v and the current as i. Draw and label the volt–ampere characteristic (i versus v).