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1. The following stack stores a stack of integers. You must draw the stacks for full credit and then determine the output of the following program. import java.util.*; public class TestStack1 { public static void main(String .. args) Stack s = new Stack<>(); s.push(-63); s.push(35); s.push(29); System.out.println(s.pop( )); Integer v = s.pop( )- s.pop() % 3; s.push(v); s.push(48); int w = s.pop( ); int x = s.pop( ); s.push(x % w + v); System.out.println(s.pop( )); Integer a=-5, b=17, c=13, d=21; s.push(a); s.push(b); s.push(c); s.push(d); s.push(s.pop( ) + s.pop( )); s.push(s.pop( ) / s.pop( )); while(!s.empty( )) {System.out.println(s.pop( ));} } Output:

1. The following stack stores a stack of integers. You must draw the stacks for full credit and then determine the output of the following program. import java.util.*; public class TestStack1 { public static void main(String .. args) Stack s = new Stack<>(); s.push(-63); s.push(35); s.push(29); System.out.println(s.pop( )); Integer v = s.pop( )- s.pop() % 3; s.push(v); s.push(48); int w = s.pop( ); int x = s.pop( ); s.push(x % w + v); System.out.println(s.pop( )); Integer a=-5, b=17, c=13, d=21; s.push(a); s.push(b); s.push(c); s.push(d); s.push(s.pop( ) + s.pop( )); s.push(s.pop( ) / s.pop( )); while(!s.empty( )) {System.out.println(s.pop( ));} } Output:

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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# Program Explanation and Output for Educational Website ## Task: The following program works with a stack of integers. The task is to simulate the operations performed on the stack and determine the output produced by the program. ## Program Code: ```java import java.util.*; public class TestStack1 { public static void main(String ... args) { Stack<Integer> s = new Stack<>(); s.push(-63); s.push(35); s.push(29); System.out.println(s.pop()); Integer v = s.pop() - s.pop() % 3; s.push(v); s.push(48); int w = s.pop(); int x = s.pop(); s.push(x % w + v); System.out.println(s.pop()); Integer a=-5, b=17, c=13, d=21; s.push(a); s.push(b); s.push(c); s.push(d); s.push(s.pop() + s.pop()); s.push(s.pop() / s.pop()); while(!s.empty()) { System.out.println(s.pop()); } } } ``` ## Explanation of the Program: 1. **Stack Initialization and Operations:** - A stack `s` is created and integers are pushed in the following order: `-63`, `35`, `29`. - The program pops and prints the top element of the stack: `29`. - The value `v` is calculated using the next two elements of the stack: `35 - (-63 % 3)` which results in `38`. 2. **Further Stack Manipulations:** - The value `38` is pushed onto the stack followed by the integer `48`. - The top value (`48`) is popped and stored in `w`, followed by popping the next value (`38`) into `x`. - The expression `x % w + v` is evaluated, resulting in `38`, which is then pushed back onto the stack. - The program pops and prints the top element: `38`. 3. **Second Set of Stack Operations:** - New integers are pushed onto the stack: `-5`, `17`, `13`, `21`. - The top two numbers are popped (`21` and `13`), their sum `34` is pushed onto the stack. - A division operation is executed
Transcribed Image Text:# Program Explanation and Output for Educational Website ## Task: The following program works with a stack of integers. The task is to simulate the operations performed on the stack and determine the output produced by the program. ## Program Code: ```java import java.util.*; public class TestStack1 { public static void main(String ... args) { Stack<Integer> s = new Stack<>(); s.push(-63); s.push(35); s.push(29); System.out.println(s.pop()); Integer v = s.pop() - s.pop() % 3; s.push(v); s.push(48); int w = s.pop(); int x = s.pop(); s.push(x % w + v); System.out.println(s.pop()); Integer a=-5, b=17, c=13, d=21; s.push(a); s.push(b); s.push(c); s.push(d); s.push(s.pop() + s.pop()); s.push(s.pop() / s.pop()); while(!s.empty()) { System.out.println(s.pop()); } } } ``` ## Explanation of the Program: 1. **Stack Initialization and Operations:** - A stack `s` is created and integers are pushed in the following order: `-63`, `35`, `29`. - The program pops and prints the top element of the stack: `29`. - The value `v` is calculated using the next two elements of the stack: `35 - (-63 % 3)` which results in `38`. 2. **Further Stack Manipulations:** - The value `38` is pushed onto the stack followed by the integer `48`. - The top value (`48`) is popped and stored in `w`, followed by popping the next value (`38`) into `x`. - The expression `x % w + v` is evaluated, resulting in `38`, which is then pushed back onto the stack. - The program pops and prints the top element: `38`. 3. **Second Set of Stack Operations:** - New integers are pushed onto the stack: `-5`, `17`, `13`, `21`. - The top two numbers are popped (`21` and `13`), their sum `34` is pushed onto the stack. - A division operation is executed
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