1.  How many milliliters of 53.40(±0.06) (w/w) % NaOH with a density of 1.52(±0.01)g/mL will you need to prepare 1.000 L of 0.200 M NaOH?  Keep 1 extra sig fig in your answer (4).

2.A

Calculate the grams of analyte per gram of precipitate for the following conversions:

The mystery fuel speedster! (Homework ) For fun, you build an explosive car with your little brother by attaching wheels to an empty windshield washer container. To advance it, you add 1.20 ml (  = 0.7915 g/ml) of a liquid but volatile fuel into the container. You close the cap and shake to evaporate the liquid. Finally, you place the car on its wheels, remove the cap and insert a burning wooden rod into the container. A flame suddenly comes out of the car, which is propelled with good speed in front of your little brother surprised, but all upset by the maneuver.   The volatile fuel is composed of 37.5% carbon, 12.6% hydrogen and 49.9% oxygen. Its molar mass is approximately 32.0 g/mol.   During the reaction, the fuel (gaseous) burns in the presence of gaseous oxygen, and the products of the reaction are carbon dioxide and water, gaseous too. The volume of the windshield washer container used is 4.00 litres. Useful Info: There is 21.0% gaseous oxygen in the air and initial conditions…

11. Calculate the mass of salt present in 1m³ of seawater with a density of 1,030 kgm-³. (a) 300.0 kg (b) 40.0 kg (c) 30.0 kg (d) 38.6 kg

What is the molarity (M) of a solution containing 72.3 grams of potassium nitrate (MM = 101.11 g/mol) in a total volume of 750.0 mL? Group of answer choices 0.953 M 9.53 x 10E(-3) 9.53 x 10E(-4) 9.53 x 10E(-2)

On an emergency cart, you have sodium bicarbonate solution (NaHCO3), 44.6 mEq/50 ml. A physician orders an aerosol of 5 cc and 3.25% strength. How many milliliters of the bicarbonate solution do you need? 1 mEq=1/1000 GEW; GEW= gram formula wt/valence Atomic weights: Na, 23; H, 1; C, 12; 0, 16

Solve the required of the following and show the complete process to be able to gain the value of the correct answer. Given:  Volume of Vinegar used (ml) = 25.00 mL Volume after dilution = 250.00 mL Volume of Aliquot used (ml) = 50.00 mL Volume NaOH used (ml) = 34.85 mL Concentration of NaOH = 0.09919475765 M Required:  Calculate % (w/v) CH3COOH = ? P.S. Use weight in grams and volume of vinegar in mL, but correction based on aliquot should be made.

5)  It was determined that [H+] was 0.0358 M in an initially 0.68 M solution of H A. What is the new [H A] with the correct number of significant figures?

Express your answer using two significant figures. HA, a weak acid, with Ka = 1.0 × 10-8, also forms the ion HA,. The reaction is НА (ад) + А (ад) —D НА, (ад) and its K %-D 4.0. - 4 [H*] = 1.0 • 10 M Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B Calculate the A in a 1.0 M solution of HA. Express your answer using two significant figures. n ΑΣφ- ? [A¯] = M Submit Request Answer Part C Calculate the HA,] in a 1.0 M solution of HA. Express your answer using two significant figures. 圈] ? [HA,] = M Submit Request Answer