Exercise 1 - Review (Substitution Cipher)
1. The ciphertext below was encrypted using a substitution cipher. Decrypt the ciphertext without knowledge of the key.
ywkdmkmj lbmbr nkwerulwbt orkrumh lmkbjl wl m surywru pwopru-rdnvmbwjk wklbwbnbwjk vjyywbbrd bj jxxruwko mxxjudmlhr mkd ravrhhrkb rdnvmbwjk bj wbl vhwrkbl xujy mvujll ywkdmkmj mkd jbpru krwopljuwko urowjkl. bpr nkwerulwbt pml lmvvmhmnurmbr mkd sjlb-lmvvmhmnurmbr drourr sujoumyl wk mouwvnhbnur, xwlpruwrl, rkowkrruwko, rdnvmbwjk, lnlwkrll mdywkwlbumbwjk mkd mvvjnkbmkvt, kmbnumh lvwrkvrl mkd ymbprymbwvl, mkd ljvwmh lvwrkvrl mkd pnymkwbwrl, oumdnmbr lbndwrl, mkd hmc. m knylru jx cpwvp mur mvvurdwbrd nkdru bpr mvvurdwbwko morkvt jx vpmubrurd vjhhrorl mkd nkwerulwbwrl wk bpr spwhwsswkrl. wb mhlj jxxrul lmlwv rdnvmbwjk sujoumyl bpujnop wbl jnkwju pwop lvpjjh mkd lrkwju pwop lvpjjh drsmubyrkbl. msmub xujy wbl ymkdmbr jx wklbunvbwjk, bpr nkwerulwbt suwdrl wbl rabrklwer rkomoryrkb wk urlrmuvp mkd rabrklwjk bpmb lrkrxwb bpr mvmdrywv vjyynkwbt mkd wbl lruewvrd lrvbjul. xnubpruyjur, yln-olv lsrmuprmdl emuwjnl wkwbwmbwerl wk srmvr mkd drerhjsyrkb ml smub jx wbl ewlwjk jx lrvjywko m kmbwjkmh srmvr nkwerulwbt.
Pointers:
1. Compute the relative frequency of all letters A...Z in the ciphertext. You may want to use a tool such as the open-source program CrypTool [50] for this task. However, a paper and pencil approach is also still doable.
2. Decrypt the ciphertext with the help of the relative letter frequency of the English language.
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- 2. Encrypt the word SHIELD using an alphabetic Caesar shift cipher that starts with a shift of 8 (A to I) and shifts one additional space after each character is encrypted. Original A BC|DE F GHI J KLMN 0PQR STUV WXY Z Maps to I J KLMNOPQRS TUVW XYZ ABCDE FGH Write the encrypted message for the word SHIELD:arrow_forwardUse the modified Caesar cipher described in the assignment instructions to decrypt the following:Ciphertext: UCTOTBWVUCKey: 5arrow_forwardDecrypt this Rail Fence/Caesar Cipher MKBOCI IZX DKDY YQCZBSSK MZIR Hint: This a split key - one part of the key is used for the Caesar and the other part of the key is used for the Rail Fence. The full key (Caesar and Rail Fence], in hexidecimal, is: 0xAB. Decrypt message: The Caesar key, in decimal, is: The Rail Fence key, in decimal, is : Is the Caesar key a good random number? . Why? Why not?arrow_forward
- 6. Confusion hides the relationship between the ciphertext and the plaintext. i) True ii) Falsearrow_forwardDecrypt the following ciphertext using frequency analysis, and explain the entire process. Even if you don’t achieve the complete decryption, you can still get full credit as long as you properly demonstrate the methodology. “FX IWBBJX PB NB PB PWX GBBD. VSP FWO, JBGX JRO, PWX GBBD? FWO IWBBJX PWUJ RJ BSA NBRK? RDL PWXO GRO FXKK RJM FWO IKUGV PWX WUNWXJP GBSDPRUD? FWO, 35 OXRAJ RNB, EKO PWX RPKRDPUI? FWO LBXJ AUIX CKRO PXQRJ? FX IWBBJX PB NB PB PWX GBBD UD PWUJ LXIRLX RDL LB PWX BPWXA PWUDNJ, DBP VXIRSJX PWXO RAX XRJO, VSP VXIRSJX PWXO RAX WRAL, VXIRSJX PWRP NBRK FUKK JXATX PB BANRDUZX RDL GXRJSAX PWX VXJP BE BSA XDXANUXJ RDL JMUKKJ, VXIRSJX PWRP IWRKKXDNX UJ BDX PWRP FX RAX FUKKUDN PB RIIXCP, BDX FX RAX SDFUKKUDN PB CBJPCBDX, RDL BDX FWUIW FX UDPXDL PB FUD, RDL PWX BPWXAJ, PBB.”arrow_forwardAffine Cipher: Find Key and Decrypt to original plaintext HMHUDUHHCQUHHFZCQHCCHFFHHPUHHIQUHRHGTHGHDPCQPCWRPKHFQZLQNNarrow_forward
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