1. An inspector measured the full volume of a simple random sample of n-100 cans of ju that were labeled as containing 12 oz. The sample had a mean volume 11.98 oz and a standard deviation of 0.19 oz. Let u represent the mean fill volume for all cans of juice recently filled by the machine. Perform a hypothesis test that u- 12 versus u+ 12 at the a- 0.05 significance level. fjuice

Use a 0.05 significance level to test the claim that males and females have the same mean BMI Male BMI n=80 * = 26.3 s = 5.4 Female BMI n=61 I = 28.4 s = 7.4

5.37 Dental anxiety study. To gauge their fear of going to a den- tist, a random sample of adults completed the Modified Dental Anxiety Scale questionnaire (BMC Oral Health, Vol. 9, 2009). Scores on the scale range from zero (no anx- iety) to 25 (extreme anxiety). The mean score was 11 and the standard deviation was 4. Assume that the distribution of all scores on the Modified Dental Anxiety Scale is ap- proximately normal with µ = 11 and o = 4. a. Suppose you score a 10 on the Modified Dental Anxiety Scale. Find the z-value for your score. b. Find the probability that someone scores between 10 and 15 on the Modified Dental Anxiety Scale. c. Find the probability that someone scores above 20 on the Modified Dental Anxiety Scale.

The average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-month period. A random sample of 42 moviegoers from a large university revealed that the average number of movies seen per person was 9.9. The population standard deviation is 3.2 movies. At the 0.05 level of significance, can it be concluded that this represents a difference from the national average?

In a random sample of​ males, it was found that 21 write with their left hands and 210 do not. In a random sample of​ females, it was found that 56 write with their left hands and 440 do not. Use a 0.05 significance level to test the claim that the rate of​ left-handedness among males is less than that among females. Identify the test statistic. and p value

In a test of the effectiveness of garlic for lowering​ cholesterol, 4949 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes​ (before minus​ after) in their levels of LDL cholesterol​ (in mg/dL) have a mean of 0.30.3 and a standard deviation of 2.142.14 Use a 0.100.10 significance level to test the claim that with garlic​ treatment, the mean change in LDL cholesterol is greater than 00. What do the results suggest about the effectiveness of the garlic​ treatment? Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative​ hypotheses?     A. Upper H 0H0​: muμequals=00 ​mg/dL Upper H 1H1​: muμless than<00 ​mg/dL   B. Upper H 0H0​: muμequals=00 ​mg/dL Upper H 1H1​: muμgreater than>00 ​mg/dL   C. Upper H 0H0​: muμequals=00 ​mg/dL Upper…

A random sample of 15 hourly wages for restaurant servers (including tips) was drawn from a normal population. The sample mean and sample standard deviation were $14.9 and $6.75 respectevely.Can we infer at the 5% significance level that the mean wage for restaurant servers (including tips) is greater than 12?

Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.02, y = 100.75, r = 0.852, P-value = 0.000, and y = 5.93 + 0.94x, where x represents the IQ score of the husband. Find the best predicted value of y given that the husband has an lQ of 100? Use a significance level of 0.05. %3D Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is Critical values of the pearson correlation coefficient r (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r X = 0.05 a = 0.01 INOTE: To test Ho: p=0 n Jagainst H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 0.878 0.959 0.811 0.917 7 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444…

In a test of the effectiveness of garlic for lowering​ cholesterol, 4949 subjects were treated with raw garlic. Cholesterol levels were measured before and after the treatment. The changes​ (before minus​ after) in their levels of LDL cholesterol​ (in mg/dL) have a mean of 0.40.4 and a standard deviation of 23.823.8. Use a 0.010.01 significance level to test the claim that with garlic​ treatment, the mean change in LDL cholesterol is greater than 00. What do the results suggest about the effectiveness of the garlic​ treatment? Assume that a simple random sample has been selected. Identify the null and alternative​ hypotheses, test​ statistic, P-value, and state the final conclusion that addresses the original claim.   Determine the test statistic.   nothing ​(Round to two decimal places as​ needed.)