1. A student shines a red laser at two slits in a piece of paper. The slitsare 0.080 mm apart. A screen is placed 2.0 m away from the slits.Upon taking measurements, the student determines that⚫ there are 5.0 cm between the first and fourth nodal lines.• the distance from the centre of the pattern to the third nodal line is4.2 cm.⚫ the angle to the eighth anti-nodal line from the right bisector is 3.8°.Perform three different calculations to determine the wavelength of thislight. Account for any difference in values.

To solve this problem, we'll calculate the wavelength of the light using three different methods…

Answered: 1. A student shines a red laser at two…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Can someone please explain ://
On a sunny day, a person's eye has a diameter of 0.00220 m. Two objects are 48.4 m from the eye. Using 550 nm light, how far apart must they be in order for the eye to resolve them? [? ]m Remember: nano means 10-9
#28 Monochromatic light with a wavelength of 6.4 E−7 meter passes through two narrow slits, producing an interference pattern on a screen 4.0 meters away. The first order bright band lines is 2.0 E−2 meters away from the central bright maxima.What is the distance between the slits? a 1.3 E−4 m b 8.0 E−6 m c 3.2 E−9 m d 7.8 E3 m
3) A double-slit experiment has slit spacing 0.10 mm. What should be the slit-to-screen distance L if the bright fringes are to be 4.0 mm apart when the slits are illuminated with 633-nm laser light?
Q2) Two microscope slides are placed together but held apart at one end by a thin piece of tin foil. Under sodium light (589 nm) normally incident on the air film formed between the slides, one observes exactly 25 bright fringes from the edges in contact to the edge of the tin foil, the thickness of the foil is [cm] a. 4.27*10-4 b. 7.22*10-4 c. 1.02*10-3 d. 1.31*10-3 e. 7.36*10-4
Lasers and Diffraction Gratings: If you had a grating that contained fewer lines per meter than another, what differences would you expect? Explain.
nd thin lenses 1- Line spacing for double-slit interference. A screen EXAMPLE 24-1 containing two slits 0.100 mm apart is 1.20 m from the viewing screen. Light of wavelength A = 500 nm falls on the slits from a distant source. Approximately how far apart will adjacent bright interference fringes be on the screen? FIGURE 24-10 Examples 24-1 and 24-2. For small angles 6 (give o in radians), the interference fringes occur at distance x = 6l above the center fringe (m 0); 0, and x, are for the first-order fringe (m 1): 02 and x2 are for m = %3D 2.
A double slit is illuminated simultaneously with a laser wavelength, λ1 =620 nm and another laser with unknown wavelength, λ2 . The m = 5 bright fringe of the unknown laser overlaps with the bright fringe m = 3 of the λ1 laser. Determine the wavelength of λ2 laser
Q4:The change of refractive index transparent materials such as glass can be given by relationship with wavelength in (Cauchy equation) n = A + B. As the (A,B) are constants and wavelength in a vacuum o. Find the group velocity at ho %3D 500 nm and for a specific type of glass it has (A=1.5, B = 3x 104 (nm)²).
Interference A laser emitting light of wavelength 550 nm is used to illuminate two parallel slits, giving two coherent sources. Interference fringes are produced on a screen 3.0 m from the slits. The separation of the fringes is 3.3 mm. a) Calculate the distance between the centres of the two slits. b) State how the separation of the fringes changes if light of a shorter wavelength were used. c) With reference to the term path difference, explain why the bright fringes are observed on the screen.
#4
Problem 4 | The full width at half maximum (FWHM) of the central diffraction maximum is defined as the angle between the two points in the pattern where the intensity is one-half that at the center of the pattern. (a) Show that the intensity drops to one-half of the maximum value when sin² a = a²/2. (b) Verify that a = 1.39 radians (about 80°) is a solution to the transcendental equation of part (a). (c) Show that the FWHM is A0 = 2 sin ¹ (0.443\/a). (d) Calculate the FWHM of the central maximum for slits whose widths are 1.0, 5.0, and 10 wavelengths.

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