Q1:A. Answer in True or False1. A soil has a Cu =1, then it is considered as a poorly graded soll.2. A soil has L.L-60% and P.L-35%, then it plots a point below the A-line in the plasticity car3. A soil described with a symbol (SP) has % passing No. 200 sieve more than 50%4. Decreasing water content below shrinkage limit is accompanied with a decreasing in void ra5. Water molecules are considered polar and known as dipoles.6. Dry Density is the smallest density.7. Capillary rise is directly proportional to the pore channel diameter.8. The unconfined compressive strength is twice the undrained cohesion.9. Piping or boiling occurs when effective stress equals to zero.10. It is assumed that the secondary compression begins when the primary conso

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1. A soil has a Cu =1, then it is considered as a poorly graded soll. 2. A soil has L.L-60% and P.L-35%, then it plots a point below the A-line in the plasticity char 3. A soil described with a symbol (SP) has % passing No. 200 sieve more than 1 4. Decreasing water content

1. A soil has a Cu =1, then it is considered as a poorly graded soll. 2. A soil has L.L-60% and P.L-35%, then it plots a point below the A-line in the plasticity char 3. A soil described with a symbol (SP) has % passing No. 200 sieve more than 1 4. Decreasing water content

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Weight-Volume relationships

Weight is defined as the quantity of matter contained in a body. Weight can also be defined as the force acting on a body due to gravity. Mathematically, weight can be defined as-

Question

Q1:
A. Answer in True or False
1. A soil has a Cu =1, then it is considered as a poorly graded soll.
2. A soil has L.L-60% and P.L-35%, then it plots a point below the A-line in the plasticity car
3. A soil described with a symbol (SP) has % passing No. 200 sieve more than 50%
4. Decreasing water content below shrinkage limit is accompanied with a decreasing in void ra
5. Water molecules are considered polar and known as dipoles.
6. Dry Density is the smallest density.
7. Capillary rise is directly proportional to the pore channel diameter.
8. The unconfined compressive strength is twice the undrained cohesion.
9. Piping or boiling occurs when effective stress equals to zero.
10. It is assumed that the secondary compression begins when the primary conso

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A. Answer in True or False 1. A soil has a Cu =1, then it is considered as a poorly graded soil. 2. A soil has L.L360% and P.L-35%, then it plots a point below the A-line in the plasticity chart. 3. A soil described with a symbol (SP) has % passing No. 200 sieve more than 50%. 4. Decreasing water content below shrinkage limit is accompanied with a decreasing in void ratio. 5. Water molecules are considered polar and known as dipoles. 6. Dry Density is the smallest density. 7. Capillary rise is directly proportional to the pore channel diameter. 8. The unconfined compressive strength is twice the undrained cohesion. 9. Piping or boiling occurs when effective stress equals to zero. 10. It is assumed that the secondary compression begins when the primary consolidation ends.
The results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58.The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by USCS system a. CH b. SP-SC c. CL-ML d. CL-ML
22. For a soil specimen, the following are given: % passing Sieve No. 4 = 92% % passing Sieve No. 10 = 81% % passing Sieve No. 40 = 78% % passing Sieve No. 200 = 65% LL = 48% PI = 32% a. Classify the soil by the AASHTO system. b. Classify the soil by the USCS.
B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30 = 0.35 mm D10 = 70 μm L.L = 36% P.L = 31% D8 = 2 μm 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if we = 26%. J
Note: Give me both solutions with clear steps. A) The particle size distribution for Soil 1 is shown. What are the USCS group symbol and group name of this soil? B) The particle size distribution for Soil 2 is shown. The soil is inorganic and has the following Atterberg Limit values: LL=34 and PL=29. What are the USCS group symbol and group name for this soil?
U B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30 = 0.35 mm D₁0 = 70 μm L.L = 36% P.L = 31% D8 = 2 µm 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if we = 26%.
Sr B. ( A Soil Specimen has the following characteristics: % passing No.4 sieve = 85 % passing No.200 sieve = 11 D60 = 2 mm D30=0.35 mm D₁0 = 70 μm D8=2 μm L.L = 36% P.L = 31% 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. 3. Determine the soil Liquidity index and consistency index if wc = 26%.
Question 3: For an inorganic soil the following grain - size analysis is given. U.S sieve Percent analysis 4 passing 100 10 90 20 64 40 38 80 18 200 13 For this soil, LL=23 and Pl=19, classify the soil by using a. AASHTO b. USCS c. Give group name and group symbols
Using Unified Soil Classification System, determine the following: (a) Coefficient of Gradation (b) Group Symbol. Passing No. 4 = 47 % Passing No. 200 = 10 % D10 = 3.45 mm %3! D30 = 6.29 mm De0 = 13.72 mm Plasticity for the minus No. 40 fraction: Liquid Limit = 28 % Plastic Limit = 17 % O GC-GM GP-GC O GC O Coef. Of Gradation = 0.84 O GP O Coef. Of Gradation = 3.97
The sieve analysis data for a granular soil are given below. % passing 76.2 mm sieve = 98 % passing 4.75 mm sieve = 63 % passing 0.075 mm sieve = 18 What would be the percentage of fine fraction by the USCS system? а. 18% оБ. 16% O c. 63% O d. 35% e. 98%
Question 2 Classify the following soils using the Unified soil classification system. Give the group symbol. No. 4 = 60 No. 200 = 40 LL = 26 PL = 4 A GW-GM В GW-GC c) GP-GM GM-GC
For an inorganic soil, the following grain-size analysis is given:Sieve No. % Passing4 10010 9020 6440 3880 18200 13For this soil, LL = 23% and PL = 19%. Classify the soil according to:a. The AASHTO soil classificationb. The Unified soil classification system