Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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- What will be the content of memory location 250 in decimal after exclusion of the following program (here instructions are separated by semicolons, and numbers are represented in decimal)?: LDI R3, 248; LD R1, (R3); DEC R1, R1 INC R3, R3; LD R2, (R3); ADD R2, R2, R1 ; INC R3, R3; ST (R3), R2. (do not write any blank space) Data address memory ... 248 25 249 31 250 ... ...arrow_forward10.- Consider the following code and pictureLoop1MOVLW 0x32MOVWF REG2DECFSZ REG2,FGOTO LOOP1 If the system clock frequency is aMHz and each machine cycle consumes 4 cycles of it. Calculate the delay time of the LOOP1 loop. Include the execution difference time of the DECFSZ instruction in the last cycle. Select an answerA) 0.6.sB) 6msC)6usD) 60usarrow_forwardzy Section 1.3 - IT 140: Introduct zy Section 1.3 - IT 140: Introduct X O (158) SNHU IT140 Module Or x b Answered: Run the program G Many useful programs allow + Ô https://learn.zybooks.com/zybook/SNHUIT140V3/chapter/1/section/3?content_resource_id=40688398 = zyBooks My library > IT 140: Introduction to Scripting v3 home > 1.3: Input/Output E zyBooks catalog ? Help/FAQ 8 Jose Roque CHALLENGE 1.3.4: Read user input numbers and perform a calculation. АCTIVITY Read two numbers from user input. Then, print the sum of those numbers. Hint -- Copy/paste the following code, then just type code where the questions marks are to finish the code. num1 = int(input ()) num2 = ? print(num1 + ?) Note: Our system automatically runs your program several times, trying different input values each time to ensure your program works for any values. Notes on how to solve this. See How to Use zyBooks for info on how our automated program grader works. 247772.2002516.qx3zqy7 1 2 ' Your solution goes here '' 1…arrow_forward
- 1. Translate the following algorithm to this simple computer's assembly language and then to machine language. (use the columns in a table as shown below) Label Operation Operand Address Machine Code Comments read a read b set c = 0 if a == b set c = a - 7 + (2 * b - 3) else if a == 3 set c = a b + 2 write carrow_forward14. Write C++ instructions to swap the contents of two memory cells n and m. 15. Write C++ statements to compute the expression x2 - 3x for x = 5 and to store the answer in a memory cell. 16. Write C++ instructions to compute the expression 5x2 + 23x +31 for x = 3.6 and to store the answer in a memory cell.arrow_forwardConsider the code below: main() { float b, *y; char c, *z; int a, X = &a; y = &b; z = &c; Given the memory representation of the variables of type int, char, and float: 1122 1123 1124 1125 1126 1127 1128 1129 1130 address 887.145 77 value b variable What is the correct value of the following items? (If the numerical value cannot be determined, type NA as your answer). z: *x: а: &c:arrow_forward
- Which of the following instructions JMP, CMP, JZ, and JNZ can transfer control to another point in a program uncondiotionally? a) The unconditional instruction is JZ.b) The unconditional instruction is CMP.c) The unconditional instruction is JNZ.d) The unconditional instruction is JMP.arrow_forward[1] Write a program, using the MIPS assembly language, to calculate the sum of the first 100 numbers and print the result. [2] Write a program which takes two numbers as input from user and determines which is the larger of the two numbers. The Program should also tell which of the entered numbers is even or odd. Output Welcome Enter number 1: 4 Enter number 2: 7 number 2 is greater than number 1 number 1 is EVEN. number 2 is ODD.arrow_forwardAssume a computer system has a main memory of 256 Bytes. The following is a memory byte-access trace history of a program run on this system. For example, as it is shown, the program first accesses memory address 0000 0000, and then it accesses memory address 0000 0001 and so on. Note the memory addresses are represented in binary: 00000000, 00000001, 00000010, 00000011, 00001000, 00010000, 00010001, 00000100, 00000101, 00000110, 00000111, 00001001, 00001010, 00001011, 00001100, 00001000, 00001001, 00001010, 00011100, 00011101.arrow_forward
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