College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- 5. Consider two (1 and 2) wires both having constant circular cross sectional areas: wire 1 has diameter = d, ; wire 2 has diameter = d. Potential differences are applied across each wire so that they both carry current. The current in wire 1 is I, and in wire 2 it is I, ; the the magnitude of the current density in wire 1 is J, and in wire 2 it is J,. If I,= I, and J, = (2) J, then wire diameters must be such that d, = (?) d. a. 2/2 b. V212 c. 2 d. V2 e. V214arrow_forwardIn the Bohr model of the hydrogen atom, an electron in the 8th excited state moves at a speed of 3.42 x 104 m/s in a circular path having a radius of 3.39 x 10-9 m. What is the effective current associated with this orbiting electron?arrow_forwardA spherical surfaces r= 3 m and r=5 m are perfectly conducting and the total current passing radially outward through the medium between the two surfaces is (3 A) dc calculate: a) The voltage and the resistance between the spheres and (E) in the region between them, if a conducting material has o = 0.05 $/m is present for 3arrow_forwardInstructions 50 cm 10 cm 8.0 A R = 1.0 × 10-3 N A small circular loop of wire of radius 5 cm and resistance 1E-3 Q is centered inside a large circular loop of wire of radius 50 cm. The larger loop, which initially carries a current of 8 A, is cut and its current is reduced to zero over a time interval of 1E-6 s. Our goal will be to find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.)arrow_forwardTwo VERY LONG wires are placed along parallel lines as shown below in the picture. The wire ON THE LEFT (at X:= 0) has a current going out of the page of value, I1 ='4 A. The current on the RIGHT (at X2= d) has a current going into the page of the page of value, l2 = 6 A. The point "P" is at the location (x=6.00cm, z=10.4cm) Wire 1 Wire 2 a. Find the magnitude of the magnetic field due to wire 2 at the location of wire 1 The Biot-Savart law say the direction of the magnetic field at a field point located in a direction (from source to field point) where a source wire carries a current in the î is Pxi the direction of the magnetic field due to wire2 at the location of wire1. c. Using the formula format find the force per unit length in "I.j,k" 1, 1, x B, d. Find the magnitude of the magnetic field due to wire2 at the location of field point P e. Find the unit directions for f and î and perform the cross product to determine the direction of the magnetic field due to wire2 at the…arrow_forwardInstructions 50 cm 10 cm 8.0 A R = 1.0 × 10-3 N A small circular loop of wire of radius 5 cm and resistance 1E-3 Q is centered inside a large circular loop of wire of radius 50 cm. The larger loop, which initially carries a current of 8 A, is cut and its current is reduced to zero over a time interval of 1E-6 s. Our goal will be to find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.)arrow_forwardProblem 7: A solenoid is created by wrapping a L = 35 m long wire around a hollow tube of diameter D = 4.5 cm. The wire diameter is d = 0.75 mm. The solenoid wire is then connected to a power supply so that a current of I = 4.5 A flows through the wire. Randomized Variables L= 35 m D= 4.5 cm d = 0.75 mm I= 4.5 A Part (a) Write an expression for the number of turns, N, in the solenoid. You do not need to take into account the diameter of the wire in this calculation. N = | 7 8 9. JT НOME d 1^ AL 4 5 6. a h 1 2 3 j k + END - m P VO BАСKSРАСE CLEAR DEL Submit Hint Feedback I give up! Part (b) Calculate the number of turns, N, in the solenoid. Part (c) Write an expression for the length of the solenoid (L2) in terms of the diameter of the hollow tube D, the length of the wire L and the diameter of the wire d. Assume it is constructed by using only 1 layer of loops (note that most solenoids are actually constructed with many layers, to maximize the magnetic field density). Part (d)…arrow_forwardInstructions 50 cm 10 cm 8.0 A R = 1.0 × 10-3 N A small circular loop of wire of radius 5 cm and resistance 1E-3 Q is centered inside a large circular loop of wire of radius 50 cm. The larger loop, which initially carries a current of 8 A, is cut and its current is reduced to zero over a time interval of 1E-6 s. Our goal will be to find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.)arrow_forwardA caterpillar of length 6.00 cm crawls in the direction of electron drift along a 8.20-mm-diameter bare copper wire that carries a uniform current of 38.0 A. (a) What is the potential difference between the two ends of the caterpillar? (b) Is its tail positive or negative relative to its head? (c) How much time does the caterpillar take to crawl 2.30 cm if it crawls at the drift speed of the electrons in the wire? (The number of charge carriers per unit volume is 8.49 × 1028 m-3 and resistivity of copper is 1.69 × 10-8 Ω·m.)arrow_forwardarrow_back_iosarrow_forward_ios
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