1-Static: is defined as the state of equilibrium of bodies affected by a system of force does not generate. a) moment b) acceleration c) resultant d) all options 2-The body is in equilibrium when the resultant of the force acting on it is equal a) zero b) is not equal to zero c) highest value 3-In mechanics, natural quantities are expressed in terms of three basic quantities approved in the international system of units: (SI Units) are-and- a) length, width, height b) length, time, mass c) width, mass, length d) all options 4-One body's reaction to the other occurs perpendicular to the contact surface when the two --bodies are touched. c) highest value d) less value a) winding b) rough c) smooth d) all options 5- Quantities in the science of statics are classified into two types-and- a) directional and nondirectional b) moment and couple c) moment and resultant d) all options

1-Static: is defined as the state of equilibrium of bodies affected by a system of force does not generate. a) moment b) acceleration c) resultant d) all options 2-The body is in equilibrium when the resultant of the force acting on it is equal a) zero b) is not equal to zero c) highest value 3-In mechanics, natural quantities are expressed in terms of three basic quantities approved in the international system of units: (SI Units) are-and- a) length, width, height b) length, time, mass c) width, mass, length d) all options 4-One body's reaction to the other occurs perpendicular to the contact surface when the two --bodies are touched. c) highest value d) less value a) winding b) rough c) smooth d) all options 5- Quantities in the science of statics are classified into two types-and- a) directional and nondirectional b) moment and couple c) moment and resultant d) all options

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Q2: Fill in the following blanks. 1-Static : is defined as the state of equilibrium of bodies affected by a system of force does not-- ---- generate. a) moment b) acceleration c) resultant 2-The body is in equilibrium when the resultant of the force acting on it is equal -- a) zero d) all options b) is not equal to zero c) highest value d) less value 3-In mechanics, natural quantities are expressed in terms of three basic quantities approved in the international system of units: (SI Units) are a) length, width, height b) length , time, mass c) width , mass, length d) all options 4-One body's reaction to the other occurs perpendicular to the contact surface when the two -------and----- --bodies are touched. a) winding 5- Quantities in the science of statics are classified into two types a) directional and nondirectional b) moment and couple c) moment and resultant d) all options b) rough c) smooth d) all options ------and--
ا من ۱ A ball of weight 120 N rests in a right angled groove as shown in Fig. The sides of the groove are inclined at an angle of 30° and 60" to the horizontal If all the surfaces are smooth, the reaction R, is given by V. TT 120 N 30° B 60° 1) 60 N 3) 30 N 2) 120 N 4) 103.92 N temeter 100 cm Ganessh G@NU 20:14 äc luJI 21.03.11 ...
86 ll ll 8:۳۶ م ۲۰كبث © ه Test 2/ Course 1/ Mechanics / Morning مطلوب Untitled Section F1-5 kN F2 = 13 kN -45 F3-4 kN 2 m 7 m F4- 22 kN EVa- 30 FS = 4 kN 1] What is the resultant moment of the five forces acting on the rod about point B? a) 31.5 kN.m b) 12.3 kN.m ) 26.2 kN.m d) 18.5 kN.m e) 32.1 kN.m ) 23.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point E? a) -11.3 kN.m b) -26.4 kN.m e) -6.9 kN.m d) - 32.1 kN.m ) - 30,7 kN.m f) - 15.9 kN.m 31 What is the moment of the force F1 about point D? a) - 35.4 kN.m c) - 41.9 kN.m d) - 12.1 kN.m e) - 26.7 kN.m D - 15.9 kN.m b) -39.4 kN.m 4] What is the moment of the force F2 about point E? a) 47.5 kN.m b) 61.5 kN.m e) 22.2 kN.m d) 69.5 kN.m ) 77.1 kN.m ) 36.1 kN.m Activate Windows Go to Settings to activate Wir f) - 25.9 kN.m 5] What is the moment of the force F5 about point B? a) - 16.8 kN.m b) -11.4 kN.m c) - 25.9 kN.m d) - 9.1 kN.m e) - 1.7 kN.m ;The answer is [1 * a h.
F1-5 kN F2 13 N 3-4N 4m Figure 1 m F4 22 kN E a-30 FS =4 kN In figure 1, find the followings: 1] What is the resultant moment of the five forces acting on the rod about point A? a) 3.5 kN.m b) 16.2 kN.m c) 20.2 kN.m d) 11.5 kN.m e) 33.1 kN.m ) 8.1 kN.m g) None of them 21 What is the resultant moment of the five forces acting on the rod about point C? a) 47.5 kN.m b) 55.5 kN.m c) 12.2 kN.m d) 61.9 kN.m e) 79.1 kN.m f) 44.1 kN.m g) None of them 3] What is the moment of the force F1 about point E? a)-22.8 kN.m b) - 49.5 kN.m c) - 55.9 kN.m d) - 9.1 kN.m e) - 12.7 kN. m f) - 25.9 kN.m g) None of them 41 What is the moment of the force F2 about point D? a) 40.5 kN.m b) 71.5 kN.m c) 14.2 kN.m d) 64.5 kN.m e) 56.1 kN.m f) 39.1 kN.m g) None of them 5) What is the moment of the force F5 about point A? a)-17.8 kN.m b)- 4.8 kN.m c)-12.9 kN.m d)-8.1 kN.m e) - 32.7 kN.m )-2.9 kN.m g) None of them
A 1:19 ۳۶۸۹ من ۳۶۸۹ F1= 10 kN F2 = 26 kN - 60 F3=8 kN 45 4 m 8m F4 = 44 KN E 30 F5 =8 kN 1] What is the resultant moment of the five forces acting on the rod about point A? a) 32.4 kN.m b) 22.5 kN.m c) 44.1 kN.m d) 19.5 kN.m e) 9.1 kN.m ) 21.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point C? a) 149.5 kN.m b) 33.5 kN.m c) 123.9 kN.m d) 111.5 kN.m e) 42.1 kN.m f) 29.1 kN.m 3] What is the moment of the force F1 about point E? a) - 98.9 kN.m b) - 59.8 kN.m e)- 114.8 kN.m d) - 77.1 kN.m e) - 29.7 kN.m f) - 66.9 kN.m 41 What is the moment of the force F2 about point D? a) 112.5 kN.m b) 33.5 kN.m e) 129.1 kN.m d) 99.5 kN.m e) 55.1 kN.m f) 29.1 kN.m 5] What is the moment of the force F5 about point A? a) - 9.6 kN.m b) - 18.8 kN.m c) - 39.8 kN.m d) - 2.1 kN.m e) - 24.7 kN.m f)-44.9 kN.m 6.T II
The stress-strain diagram of a reinforcement steel having a cross-sectional diameter of 12 mmdiameter and 100 mm gage length is determined after its tensile strength test as follows. Based on the stressstrain diagram determine the followings properties of the material (Poisson’s ratio of the material is 0.32) : a) Modulus of elasticityb) Yield strengthc) Toughnessd) Resiliencee) Shear modulusf) Bulk modulusg) Ductility as described bypercent change in length
F1-5 kN F2 13 N 4m Figure 1 F4 22 kN EJ-30 FS =4 kN In figure 1, find the followings: 1] What is the resultant moment of the five forces acting on the rod about point A? a) 3.5 kN.m b) 16.2 kN.m c) 20.2 kN.m d) 11.5 kN.m e) 33.1 kN.m ) 8.1 kN.m g) None of them 21 What is the resultant moment of the five forces acting on the rod about point C? a) 47.5 kN.m b) 55.5 kN.m c) 12.2 kN.m d) 61.9 kN.m e) 79.1 kN.m f) 44.1 kN.m g) None of them 3] What is the moment of the force F1 about point E? a)-22.8 kN.m b) - 49.5 kN.m c) - 55.9 kN.m d) - 9.1 kN.m e) - 12.7 kN. m f) - 25.9 kN.m g) None of them 41 What is the moment of the force F2 about point D? a) 40.5 kN.m b) 71.5 kN.m c) 14.2 kN.m d) 64.5 kN.m e) 56.1 kN.m f) 39.1 kN.m g) None of them 5) What is the moment of the force F5 about point A? a)-17.8 kN.m b)-4.8 kN.m c)-12.9 kN.m d)-8.1 kN.m e) - 32.7 kN.m )-2.9 kN.m g) None of them
Q2: A general system of forces and couple moments acting on a rigid body can be reduced to a A) Single force B) Single moment C) Single force and two moments D) Single force and a single moment
Questions 1,2 and 3 In the figure shown, if F, 250 lb, and F₂= 200 lb, Determine the following: 1) The magnitude of the component of F, along the u axes: a) 482.9 lb b) 386.3 lb c) 289.7 lb d) 193.1 lb e) None 2) The magnitude of the component of F2 along the v axes: a) 433 lb b) 346.4 lb c) 259.8 lb' d) 519.6 lb e) None 3) The magnitude of the resultant force of Fi and F₂: a) 216.7 lb b) 256.1 lb c) 314.5 lb U d) 276.8 lb 30° 30° 45⁰ e) None F₁
F1 = 5 kN F2 = 13 kN 0 = 45° B - 60° F3 = 4 kN A В 4 m 3. 8 m F4 = 22 kN a = 30° F5 = 4 kN 1] What is the resultant moment of the five forces acting on the rod about point A? a) 3.5 kN.m b) 16.2 kN.m c) 20.2 kN.m d) 11.5 kN.m e) 33.1 kN.m f) 8.1 kN.m 21 What is the resultant moment of the five forces acting on the rod about point C? a) 47.5 kN.m b) 55.5 kN.m c) 12.2 kN.m d) 61.9 kN.m e) 79.1 kN.m f) 44.1 kN.m 3] What is the moment of the force F1 about point E? а)- 22.8 kN.m b) - 49.5 kN.m c) – 55.9 kN.m d) - 9.1 kN.m e) - 12.7 kN.m f) - 25.9 kN.m 4] What is the moment of the force F2 about point D? a) 40.5 kN.m b) 71.5 kN.m c) 14.2 kN.m d) 64.5 kN.m e) 56.1 kN.m f) 39.1 kN.m 5] What is the moment of the force F5 about point A? а)-17.8 kN.m b) - 4.8 kN.m c) – 12.9 kN.m d) - 8.1 kN.m e) - 32.7 kN.m f) – 2.9 kN.m
4) A piston/cylinder is arranged as in the figure below. How much work is done when the piston moves from position 1 to position 2? a) 1W2 = P₁(V₂ -v₁) b) 1W₂ = V₁ (P₂ - P₁) C) d) e) TW₂ 1/² (P₂ + P₁) (V₂ − v₁) - (P₂ - P₁) (v₂ + v₁) (v² − v²) - 1W2 = 1W₂ = Spring W P1,0₁ 2
1) A piston-cylinder system containing 1100 grams of an ideal gas ‘X’ is cooled from 900 K to 100 K at constant pressure. The specific heat capacity of the gas is Cp = 38.3 J.mol-1.K-1. Assume Cp stays constant in the given temperature range. The molar mass of the gas = 28 g.mol-1. a) Write the simplified first law of thermodynamics for this system with justification. b) Calculate the total heat transferred (in kJ) during the process of cooling c) If the entire heat from the cooling of ‘X’ (as calculated in (b)) could be used as work to change the volume of another gas ‘Y’ from 500 m3 to 1000 m3 in a constant pressure process, calculate the value of pressure. d) Instead of cooling at constant pressure, if ‘X’ was expanded reversibly and at a constant temperature (300K), calculate the work done by the system in kJ if the change in volume was 10-fold.