1) A piston-cylinder system containing 1100 grams of an ideal gas ‘X’ is cooled from 900 K to 100 K at constant pressure. The specific heat capacity of the gas is Cp = 38.3 J.mol-1.K-1. Assume Cp stays constant in the given temperature range. The molar mass of the gas = 28 g.mol-1. a) Write the simplified first law of thermodynamics for this system with justification. b) Calculate the total heat transferred (in kJ) during the process of cooling c) If the entire heat from the cooling of ‘X’ (as calculated in (b)) could be used as work to change the volume of another gas ‘Y’ from 500 m3 to 1000 m3 in a constant pressure process, calculate the value of pressure. d) Instead of cooling at constant pressure, if ‘X’ was expanded reversibly and at a constant temperature (300K), calculate the work done by the system in kJ if the change in volume was 10-fold.

How much ice (by mass) at a temperature of -19.9 degrees Celsius must be added to 325g of liquid water at a temperature of 60.1 degrees Celsius in order for the final temperature of both to reach 21 degrees Celsius. c of ice=2100 J/kg/C c of water=4190 J/kg/C Latent heat of fusion of water=3.34E5 J/kg/C a. .115kg b. 12kg c. 5 lbs d. .191kg

a) Determine the density (p), specific gravity (SG), and mass (m) of the air in a room as shown in Figure 1 at 100 kPa and 25°C, if the gas constant of air is R = 0.287 kPa . m³/kg . K. 4 m ..... .. 5 m 6 m Figure 1 b) What is the pressure head in mmHg, exerted by the atmosphere?

Q 1 please

1.2 2 2.50 WP A gas undergoes a process in a piston-cylinder assembly during which the pressure-specific volume relation is pul2 = con- stant. The mass of the gas is 0.4 lb and the following data are known: P₁ = 160 lbf/in.², V₁ = 1 ft³, and p₂ = 390 lbf/in. During the process, heat transfer from the gas is 2.1 Blu. Kinetic and potential energy ef- fects are negligible. Determine the change in specific internal energy of the gas, in Btu/lb.

2. a. Take B °C, then convert it to Fahrenheit and Kelvin. b. Find the amount of heat needed to change the temperature of B g of ice from -D °C to B °C. The specific heat of water is 4186 J/kg °C, Latent heat of fusion is 3.33 x105 J/kg, laten heat of vaporization 2.25 x 106 J/ kg. c. A patient of mass B kg is spiking a fever of 105 Fahrenheit. The patient is immersed in ice bath 0°C ice to reduce the fever immediately back down to 98.6 Fahrenheit. How much ice must melt (bath stays at 0°C water) for this temperature reduction to be achieved? Latent heat of fusion is 3.33 x105 J/kg. and Specific heat of body is 3500 J/kg °C. d. A Styrofoam ice box has a total area of C/100 m² and walls with an average thickness of 2.50 cm. The box contains beverages at 0°C. The inside of the box is kept cold by melting ice. How much ice melts in one day if the ice box is kept in the trunk of a car at 35.0°C? Thermal conductivity of ice 0.010 J/s m ºC, Latent heat of fusion is 3.33 x105 J / kg. B:27.0…

Please explain and answer

a) You have two phases of liquid and vapor (i.e., wet steam) at 250°C in a high-temperature high-pressure vessel, which contains 0.8 grams of vapor and 5 grams of liquid. What is the specific volume of the vapor (ml/g)? b) What is the total volume (mL) of the vessel? c) The vessel temperature was increased from 250°C to 280°C wile keeping the volume from part b the same. What is the mass (grams) of liquid then? 978 Appendix A.III: The Thermodynamic Properties of Water and Steam Saturated Steam: Temperature Table (Continued) Specific Volume Sat. Liquid VL 175 180 185 190 195 Temp (°C) T 200 205 210 215 220 225 230 235 240 245 250 255 260 265 270 275 280 285 290 295 300 305 310 315 320 330 340 350 360 370 Press. (MPa) P 0.8920 0.001 121 1.0021 0.001 127 0.001 134 1.1227 1.2544 0.001 141 1.3978 0.001 149 1.5538 0.001 157 1.7230 0.001 164 1.9062 0.001 173 2.104 0.001 181 2.318 0.001 190 2.548 0.001 199 2.795 0.001 209 3.060 0.001 219 3.344 0.001 229 3.648 0.001 240 3.973 0.001 251 4.319…

I have some things that need clarification based on the answer provided to this question. Firstly, the h1 value came out as 154.99 kJ/Kg for me not 153.318. Also, the values taken from the steam table for Vf and Vg for 5 degrees celcius and 6 degrees are different from what is on the steam table, I have attached a picture for this. For 5 degrees on the steam table it shows Vf as 0.00100008 and Vg as 147.011 and for 6 degrees it shows Vf as 0.00100011 and Vg as 137.633. Please clarify this and reply as soon as possible. Thanks

Thermodynamics  Chapter 3  Complete the following table for water demonstrate clearly how you are getting the answers.