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- The output of the folloung than Vpo-VT. crravit cannot go (Voo = 1V,VT=03 V,ignore the baby eftect). eftfect). out in a) why? (kink: Vgs LUz → Io=0) b) What is going to be the max autput voltages for the fellaung crcuits. (laputs ore rising from o to l) b-4) in. out 0→1 b.2 ) 031. out 0-1Sketch the DC load line for the fixed bias circuit and place the Q-point on it. - (1.24 MA, Io.76V) %3D Q - Peint Vcc =+12V RC 1k2 RB 1 MQ BC107 Vc VB Quantity Measured VB 0-6 28 volt 07-82 V1t 0.628 volt VC V BEQ IBQ 0-0000|13,A A 0-00418 A 0.782 Uolt IcQ V CEQ BacA bridge full - wave rectifier with a capacitor - input filter provides a dc output voltage of 14.5 V to a 330 ohm load. Determine the value of filter capacitor if it connected to input voltage of 12 V rms, 50 Hz. Question 7Answer a. 220 ɲf b. 208 ɲfc. 440 fd. 104 nf
- 24. A step up chopper has load voltage of 600V and is sup- plied from a constant de source of 150V. If the OFF time of the chopper is 40 µs and desired output voltage is 300V find ON time of the chopper? (A) 5 µsec (C) 30 µsec (B) 10 μsec (D) 40 µsecQ19. For the circuit diagram shown in FigureB19. Vin and Vout corresponds to input and output voltage, V3 corresponds to output voltage from second stage of the circuit and A1, A2, A3 corresponds to Gain of each block. V3 =? Vin=3.5V Vout = 11.5dB Al- 6 A2-? A3-0.88 Figure B19 i) Compute the output voltage V3 and A2. ii) Whether the circuit in figure B19 will provide amplification or attenuation? Justify your answer.Q. The IC used in OPAMP is LM 741. True False
- Q2 In the circuit as shown below. Determine the (ripple factor) and sketch vp(out) for the filtered bridge rectifier with a load as indicated. 2 : 1 D3 D1 120Vp-p f= 50HZ + Output V1 V2 D2 D4 1uf R1=2k3. Graphical Representation of the signal 1) Write the type of the voltage from simulation results: 2) Write the value of the voltage from simulation result: L....... -2 DDU 12ns SónG Trace Color Trace Name X Values CURSOR 1,2 V(R1:1,0) Y1 Y2 Y1 - Y2 5.0373m 0.000 5.0373m 249.983 0.000 249.983 Y1(Cursor1) - Y2(Cursor2) Y1-Y1(Cursor1) Y2 - Y2(Cursor2) Max Y Min Y Avg Y 249.983 0.000 0.000 249.983 0.000 124.991FAIRCHILD Discrete POWER & Signal Technologies SEMICONDUCTOR ru 1N4001 - 1N4007 Features • Low torward voltage drop. 10 a14 * High aurge eurrent cepablity. 0.160 4.06) DO 41 COLOR BAND DGNOTEs CAT-Cos 1.0 Ampere General Purpose Rectifiers Absolute Maximum Ratings T-26*Cuness atnerwioe rated Symbol Parameter Value Units Average Recttied Current 1.0 375" lead length a TA - 75°C Tsargei Peak Forward Surge Current 8.3 ms single halr-sine-wave Superimposed on rated load JEDEC method) 30 A Pa Total Device Dissipetion 2.5 20 Derste above 25°C Ra Tag Thermal Resistence, Junction to Amblent 5D Storage Temperature Range 55 to +175 -55 to +150 Operating Junetion Temperature PC "These rarings are imithg valuee above whien the serviceatity or any semiconductor device may te impaired. Electrical Characteristics T-20'Cunieas ofherwise roted Parameter Device Units 4001 4002 4003 4004 4005 4006 4007 Peak Repetitive Reverse Vellage Maximum RME votage DC Reverse Voltage Maximum Reverse Current @ rated VR…
- Q1. Find the input impedance Zm(S) of each of the circuit in Figure Q1. ww 1H 1H 0.5 F 1F (a) (b) Figure Q1 all ll HThe characteristic of the UJT exhibits the following values: n = 0.575, RB1 = 10 k-ohms, Vv = 1.3 V, Iv =20mA, Ip=15UA. 125V B2 B, Determine the following: a. Determine the R82 (in kilo-ohms) of the UJT b. Determine the maximum value range of R (in kilo-ohms) that will ensure proper turn-on and turn-off of the UJT c. Determine the minimum value range of R (in kilo-ohms) that will ensure proper turn-on and turn-off of the UJT2. From the given circuit, calculate the voltage required to turn on the UJT. R1 C1 0.1 uF VBB +20V 680 R3 68 Circuit for Problem 1 and 2 UJT Specifications VP = 14.5 V IP = 500 UA Vv = 3.5 V lv = 6mA n = 0.6