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1 k : 1 kn 1 kn 's 1 kn 2V 10V E 2 kn 4 mA 2 kn 2 kn3 Vx 1 kn V. .3

1 k : 1 kn 1 kn 's 1 kn 2V 10V E 2 kn 4 mA 2 kn 2 kn3 Vx 1 kn V. .3

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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what is the value i1

what is the value i2

what is the value i3

what is the value i4

what is the value i5

what is the value i6

1 ko 31 kM 31 kn 3) 3 1 kN 2V 10V E 2 kN 4 mA 32 kn 2 kn 3Vỵ 31 kN V. Using I1, 12, 13, 14, 15, and 16 for the mesh currents in mA, write the equation for the application of KVL around the requested meshes. If it is not possible to write such an equation, please enter “NP" without the quotes:
Transcribed Image Text:1 ko 31 kM 31 kn 3) 3 1 kN 2V 10V E 2 kN 4 mA 32 kn 2 kn 3Vỵ 31 kN V. Using I1, 12, 13, 14, 15, and 16 for the mesh currents in mA, write the equation for the application of KVL around the requested meshes. If it is not possible to write such an equation, please enter “NP" without the quotes:
Expert Solution
Step 1

This question is solved using mesh analysis. Hope it helps.

Any branch containing current source already defines mesh current of the mesh containing that branch.

Therefore, i4=4mA.

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