1 #include 2 using namespace std; 7 8 /** 15 ) 23 24 "/ 12 int find next(int values[], int size, int searched value, int start) Finds the next occurrence of an element in an array. @param values an array of values @param searched value the value to search for @param start the position at which to start the search @return the position of the first match at position > start, or 1 if the element was not found 27 28 29 } int main() int a[] (3, 1, 4, 1, 5, 9, 2, 6); int found at find next(a, 8, 1, 2); cout << "find next(3, 1, 4, 1, 5, 9, 2, 6, 8, 1, 2) << endl; << "Found at: found at << endl; cout << endl; cout << "find next({ 3, found at 1, 4, 1, 5, 9, 2, 6), 8, 7, 3) << endl; find next (a, 8, 7, 3); cout << "Found at: << found at << endl; return 0;

1 #include 2 using namespace std; 7 8 /** 15 ) 23 24 "/ 12 int find next(int values[], int size, int searched value, int start) Finds the next occurrence of an element in an array. @param values an array of values @param searched value the value to search for @param start the position at which to start the search @return the position of the first match at position > start, or 1 if the element was not found 27 28 29 } int main() int a[] (3, 1, 4, 1, 5, 9, 2, 6); int found at find next(a, 8, 1, 2); cout << "find next(3, 1, 4, 1, 5, 9, 2, 6, 8, 1, 2) << endl; << "Found at: found at << endl; cout << endl; cout << "find next({ 3, found at 1, 4, 1, 5, 9, 2, 6), 8, 7, 3) << endl; find next (a, 8, 7, 3); cout << "Found at: << found at << endl; return 0;

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter8: Arrays

Section: Chapter Questions

Problem 9PE

See similar textbooks

Similar questions

In the "Common Array Algorithms" section, you learned how to find the position of an element in an array. Suppose you want to find the position of the second match. You could remove the first match and start over, but that would be wasteful. Instead, adapt the algorithm from that section so that it starts the search at a given position, not zero. Complete the following code.
Create 2D array 4 *5. Ask the user to enter the number inside the array. Print the numbers organized by rows. Calculate the average for each row. Print the least average. Finally, create a method that receives a 2D array to print its elements reverse starting from the last element.
Create an array of 15 integers. Add all elements located at ODD index positions and sum also all numbers located at EVEN(Assume zero index is even) index positions in the linear array. The user will be the one to input each item in the array of 15 elements. Display also the inputted integers in the array. Given the sample layout w/ test data below:
In [ ]: We obtained an array with N = 10 values, scattered about mean of 25 (mm). Let's calculate the mean, standard deviation, standard deviation of the mean and 20-uncertainty SL of these numbers. In the following code, do these steps: • In the first cell, add a brief comment that explains what each statement does. Start each comment with a # sign. • In the second cell, delete the raise Not ImplementedError() code line and print the standard deviation and 20-uncertainty on the screen (follow the example for mean_L) mean_L = np.mean (L) print("Mean length: ", mean_L) stddev_L = np. std (L, ddof=1) stddev_mean_L = stddev_L/np.sqrt(N) uncertainty_L = 2*stddev_mean_L In [ ] V #YOUR CODE HERE raise NotImplementedError() #calculates the mean of L In the above code, the green expressions on the right hand side, such as np.mean, np. std and np.sqrt are functions built into the numpy package of Python. The names on the left hand side are variable names invented by me.
Create a Numpy List named as marks with six float numbers, showing the final marks of a student in six subjects. Round the marks from marks array from Q-3 a) upto two decimal numbers What if you need to create the same list as Q-3 a), but for five students. Can you still use 1-D array? How many dimensions should be there?
Create an application that compares the four advanced sorting algorithms discussed in this chapter. For the tests, create a 1,000-element randomly generated array. What is the algorithm's position? What happens when you expand the array size to 10,000, then 100,000 elements?
Create a Numpy List named as marks with six float numbers, showing the final marks of a student in six subjects. Round the marks from marks array from Q-3 a) up to two decimal numbers What if you need to create the same list as Q-3 a), but for five students. Can you still use 1-D array? How many dimensions should be there? Find the highest marks a student has obtained using marks array from Q-3 a) Use seaborn to show marks array from Q-3 a)
4. Create a main method that will create a 2-d array with 4 rows and 5 columns. Call the method from number 3 to fill the array with values. Use a loop to find the max of each row and then curve each row so that the max is turns into 100.
Create a Numpy List named as marks with six float numbers, showing the final marks of a student in six subjects. Round the marks from marks array from Q-3 a) upto two decimal numbers What if you need to create the same list as Q-3 a), but for five students. Can you still use 1-D array? How many dimensions should be there? Find the highest marks a student has obtained using marks array from Q-3 a) Use seaborn to show marks array from Q-3 a)
Create 1 method to output the list of numbers. Output the list of numbers input by user. Output the average of all the numbers. Attach Snipping photos of source code and output. Task 2 Update above program. Create a Method that will return the largest element in the array. Attach Snipping photos of source code and output.
int primes={21,23,25,37,11,13,17.19,23,29,31,37,41,43,47,53,59,61,67,73,79,83,89,97}consider the above array of primes you have to search 53 n the array, also you have to check whether 53 is prime or not, also keep count of how many primes comes before 53.
given an array of integer values , return true if 6 appears as either the first or last element in the array. firstLast6([1,2,36]) true firstLast([6,1,2,3]) true firstLast([13,6,1,2,3]) false