do both methods!B1) For the truss shown to the right. Determine: a) the supportreactions at E and F, and 2) the force in member CE usingmethod of sections (specify (T) or (C)). (Note: F is a roller andE is a pin.)Ans: Ey = 9 kips (), Ex = 8 kips (), Fy = 9 kips (T)FCE = 9 kips (T)4 kips6.75 ftD.%3D4 kips%3D6.75 ftE

Answered: Image /qna-images/answer/784d1d4d-e554-4291-93da-35ba4f334c80.jpg

Answered: 1) For the truss shown to the right.…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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2) A cantilevered truss is loaded as shown below. Using method of sections determine the force in member BC. Leave your answer in terms of P. Specify tension (T) or compression (C). (FYI, you do not need a calculator to do this problem.) (Hint: you do not need to find the support reactions to do this problem.) Ans: FBC = (9P)/4 (T) 6 m 6 m 4 m D E 3 m 6 m 3 m
Use the method of sections to determine the forces in members BD, CD, and CE. Note: The support reactions given below were determined in lecture last week (“Example: Method of Joints"). [Ans.: Fsp = -4 kN (comp), FCD = 2.83 kN (tension), FCE = 1 kN (tension)] Cut b Some potential (3 unk.) y section lines 1 kN Cut c (cuts a, b̟ and c): (3 unk.) Cut a (4 unk.), 2 m 2/n 2 m 2 th 2 m → F=-1 kN F = 2 kN 5 kN A, = 3 kN %3D %3D Note: The length of each member is 2 m and hence 0 = tan-1(2 m/2 m) = 45° E.
3) Calculate the internal forces in members DF, CE, and BD of the given truss shown in the figure below. Use the Method of Sections. G0ON GOON GOON GOON G0ON 1,5m 600 N B. 600 N A 6 at 1-20m = 7.20m
1) A Warren bridge truss is shown to the below. (a) Determine the support reactions at A and K. (b) Determine the force in members CE, DE, and DF using method of joints. (c) Determine the force in members CE, DE, and DF using method of sections. (Note: A is a roller and K is a pin.) Ans: Ay = 8400 lb (1), K, = 0, Ky = 3600 lb (T), FCE = 8000 lb (T), FDE = 2600 lb (T), FDF = 9000 lb (C). [Intermediate answers for method of joints: FAB = 9100 lb (C), FAC = 3500 lb (T), FBC = 9100 lb (T), FBD = 7000 lb (C), FcD = 2600 lb (C)I %3D 6.25 ft 12.5 ft, 12.5 ft 12.5 ft, 12.5 ft В F H 15 ft K E 12.5 ft 12.5 ft 12.5 ft' 12.5 ft' 12.5 ft 6000 lb 6000 lb
Find the internal forces in members BC, CG, and EG. Indicate whether it is tension or compression. Use method-of-sections. 1000 Ib 1000 Ib 500 Ib 20in 20in 20in 20in
2) A force, P, is applied to the truss shown to the right. First, determine the support reactions at C and F. Determine the force in member AB in terms of the A В applied force P (specify tension or compression). You must do this problem: (a) first, using method of joints, (b) second, using method of sections. (For part (a), plan ahead: what is the best joint to start with, so you can minimize the number of joints you need to analyze?) (FYI, you can do this problem without a calculator problem.) Ans. C, = 2P/3 (↑), Fx = 0, F, = P/3 (↑) FAB = P/2 (C) 4 m C F E OMONO P 3 m 3 m 3 m
3) Determine the force in members EF and GI of the truss shown. The truss system is pin connected at point B and has roller at point J (Hint: If you use the method of sectioning, then you need two sections.) 28 kips 28 kips A C E G I K 16 kips 10 ft D F H. 8 ft 8 ft 8 ft 8 ft 8 ft
The truss shown in the figure below is supported on roller at A and a hinge at B. Solve for the | components of reaction. Note: use "m" for distance use "N" for unit of force 600 240 D 16' 12' 12' F 12' BH 400 Ay By MATHalino.com
2. Determine the forces in members BD, BE, CE and DE in the truss shown below using method of section where in the units are in kips (1 kip=1000 lb) H B 36' 35' 32' 27' C E G 30* 30K 30* 30* 30* 30* 30* 8 panels @ 25' = 200' %3D
Find the member forces in the truss shown below. = 4 m B - D P = 50.0 KN 4 m 3 m F(AB) - 23.6 kN (T). F(AD) 34.4 KN (T). F(CD) O F(AB) 18.2 kN (T), F(AD) - 34.4 kN (T). F(CD) - 34.4 kN (T), F(CB) C 1 m 14.4 kN (T), F(CB) www. F(AB) 18.2 kN (T), F(AD) - 34.4 kN (T), F(CD) - 34.4 kN (T). F(CB) F(AB) 23.6 kN (T), F(AD)= 34.4 kN (T), F(CD) - 34.4 kN (T), F(CB) 57.1 kN (C), F(DB) 25.4 kN (T) 47.1 kN (C), F(DB) 16.67 kN (T) 47.1 kN (C). F(DB) = 25.4 kN (T) 47.1 kN (C), F(DB) 16.67 kN (T) W M
a) What is a truss? Explain shortly in your own words, and illustrate with one example. b) For the truss in the figure below, determine the zero-force members and give a short explanation to support your answer. B C D A H -1.5 m- G F -1.5 m 1.5 m-1.5 m-- 2 m 2 m E
(a) Establish whether the 3D truss shown below is statically determinate. Justify your answer mathe- matically. (b) Apply the method of sections, with a section cut by a plane parallel to the xz plane (severing members EC, DC, EB, DB, AB) to determine the force in the member AB of the truss in the figure. (c) Compute the force in member DB. Hint: Select a line that several unknown forces pass through and sum moments of the cut section about this line. X A 2 m 4 m Elt D 3 m B 8 kN с 6 kN 10 KN

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1) For the truss shown to the right. Determine: a) the support reactions at E and F, and 2) the force in member CE using method of sections (specify (T) or (C)). (Note: F is a roller and E is a pin.) Ans: Ey = 9 kips (), Ex = 8 kips (E), Fy = 9 kips (↑) FCE =9 kips (T) %3D %3D %3D