1) A Warren bridge truss is shown to the below. (a) Determine the support reactions at A and K. (b) Determine the force in members CE, DE, and DF using method of joints. (c) Determine the force in members CE, DE, and DF using method of sections. (Note: A is a roller and K is a pin.) Ans: Ay 8400 lb (1), Kx = 0, K, = 3600 lb (↑), FCE = 8000 lb (T), FDE= 2600 lb (T), = 9000 lb (C). [Intermediate answers for method of joints: FAB = 9100 lb (C), FAC = 3500 lb (T), FBC = 9100 lb (T), FBD = 7000 lb (C), FcD = 2600 lb (C)] %3D %3D %3D FDF %3D %3D %3D %3D

International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter5: Three-dimensional Equilibrium
Section: Chapter Questions
Problem 5.26P: The figure shows the FBD of a portion of the space truss shown in Fig. P5.25. Use this FBD to find...
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1) A Warren bridge truss is shown to the below. (a) Determine the support reactions at A and K.
(b) Determine the force in members CE, DE, and DF using method of joints. (c) Determine the
force in members CE, DE, and DF using method of sections. (Note: A is a roller and K is a pin.)
Ans: Ay = 8400 lb (1), K, = 0, Ky = 3600 lb (T), FCE = 8000 lb (T), FDE = 2600 lb (T),
FDF = 9000 lb (C). [Intermediate answers for method of joints: FAB = 9100 lb (C),
FAC = 3500 lb (T), FBC = 9100 lb (T), FBD = 7000 lb (C), FcD = 2600 lb (C)I
%3D
6.25 ft
12.5 ft, 12.5 ft 12.5 ft, 12.5 ft
В
F
H
15 ft
K
E
12.5 ft
12.5 ft 12.5 ft' 12.5 ft' 12.5 ft
6000 lb 6000 lb
Transcribed Image Text:1) A Warren bridge truss is shown to the below. (a) Determine the support reactions at A and K. (b) Determine the force in members CE, DE, and DF using method of joints. (c) Determine the force in members CE, DE, and DF using method of sections. (Note: A is a roller and K is a pin.) Ans: Ay = 8400 lb (1), K, = 0, Ky = 3600 lb (T), FCE = 8000 lb (T), FDE = 2600 lb (T), FDF = 9000 lb (C). [Intermediate answers for method of joints: FAB = 9100 lb (C), FAC = 3500 lb (T), FBC = 9100 lb (T), FBD = 7000 lb (C), FcD = 2600 lb (C)I %3D 6.25 ft 12.5 ft, 12.5 ft 12.5 ft, 12.5 ft В F H 15 ft K E 12.5 ft 12.5 ft 12.5 ft' 12.5 ft' 12.5 ft 6000 lb 6000 lb
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