1) Find the true magnitude and direction of the forces at the supports A and B in the case of static equilibrium. Fig 2.1 - 200lb +y A TITXTIT A 6' -7.5' 100lb 9' तीशी 12' B B 20' Fig 2.1 FREE BODY DIAGRAM SE 100lb/ft +X +X

Problem 4c: Find the force P, required to maintain equilibrium in the position shown. Also find the support reactions in the bearings at A and B. The bearing at B supports thrust, while the bearing at A does not. 500 lb 150 lb 12 in. 12 in. 200 lb 18 in. 14 in. 14 in.

N Motor 0.2 m 0.2 m 100 kg B Given: drum, shaft, and motor diameter = 100mm Bearing supporting A and B are thrustless A & B have no moments ask: for the mass to be in equilibrium, what are? Reaction force at A Reaciton force at B Torque Mz

Figure 1 shows a railroad wagon axle and forces acting over it. There are two disc brakes on the wagon axle. Since the wagon wheels are not driven wheels, the load bearing element to which the wheels are connected is called axles. The axle is supported at both ends with bearing A and bearing B and the the weight of the wagon (G) is evenly distributed on both bearings (as G/2). During braking, two disc brakes on the axle are applied Ff force and Ft friction forces are formed on the wheels. Therefore the axle is forced to bend in the vertical direction with the effect of wagon weight (G) and wheel reaction forces (Rt), and in horizontal direction with the effect of braking (Ff) and wheel friction (Ft) forces. At the same time, the axle is forced under torsion because of Ff and Ft forces. GIVEN:Shaft material : 50CrMo4 Wheel material : GS 60 Brake discs’s material: 15Cr3 All the radiuses : 5 mm Average roughnesses for press fit surfaces: Ra =6.3 μm Wheel speed: = 500 d/d Wagon weight per…