1 Consider the complexes 2 Zr(H₂O)6]** TiC14]² 3 4 Cr(H₂O)6] Co(CN)6]³- 6 Co(CN)6] Fe(H₂O)]³+ Ni(CN)4]²- A. Give Crystal field splitting of all the complexes in the table above: B. Which compound/s is/are paramagnetic, simply write the number/numbers 1-6? C. Which compound has a metal with 5 electrons in d orbital? D. Which compound has only two unpaired electrons? E. Which compound/s is/are diamagnetic? F. Which complex could be colorless? G. Which complex is likely to be tetrahedral? H. Which compound is square planer? 1. How many unpaired electrons are in complex 4

What is the transition metal-containing product for the following reaction, where [Rh(CO)Br3]2- is a square-planar complex? [Rh(CO)Br3]2-  +  CO(g)  -->  ? Group of answer choices [RhBr4]3- an equal mixture of cis- and trans-[Rh(CO)2Br2]- trans-[Rh(CO)2Br2]- cis-[Rh(CO)2Br2]-

14. The complex ion [Ni(TAP)(CN)]+ has a distorted trigonal bipyramidal structure, the complex ion has a coordination number… A. 4B. 6C. 5D. 7

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For the complexes: 2- (1){Co(NO)6} Splitting patterm: octahedral of tetrahedral? (II) {Co(H2O)6}* Splitting pattern: octahedral of tetrahedral Strong or weak field ligand? Strong or weak field ligand? Number of unpaired electrons? Number of unpaired electrons? Which is more paramagnetic; (I) or (II)?

The spectrochemical series is                I– < Br– < Cl– < F– < OH– < H2O < NH3 < en < NO2– < CN– Which of the following complexes has the greatest number of unpaired electrons?  Select one: A. [Fe(CN)6]4– B. [Ni(CN)6]4– C. [Mn(CN)6]4–  D. Two of the complexes have an equal number of unpaired electrons that are the greatest number of unpaired electrons. E. [Co(NH3)6]3+   The correct answer should be "E," but can someone explain why it is?

) Is the complex ion [Fe(CN)6]4– inert or labile? Explain