1 2 A= |-1 -1 1 = [ ²3₁ 2 0 1 -2]

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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How did we get (1,-1,1) I need to understand I have exam , the question is: For the eigenvalue ?2 = −1, find a corresponding eigenvector.
1 2 0
+69
A=-1 -1 1
3 2 -2]
2
-1
-1 -1-> 1
2 -2-
2
2
P÷3433
(€90-8)
(₁)
1-) 2
3 2
x=-y
X=Z
1₂=-1
2
2
1
C
2х+2y=0
-X+z=0
3x +2y-z=0
Transcribed Image Text:1 2 0 +69 A=-1 -1 1 3 2 -2] 2 -1 -1 -1-> 1 2 -2- 2 2 P÷3433 (€90-8) (₁) 1-) 2 3 2 x=-y X=Z 1₂=-1 2 2 1 C 2х+2y=0 -X+z=0 3x +2y-z=0
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