0 25 50 20 Depth 20 19 19 18 16 14 12 75 100 125 10 Depth| 17 15 14 2- 50 175 200 150 50 100 150 200 Distance from center Depth 10 (in feet) Depth (in feet)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

A pond is approximately circular, with a diameter of 400 feet. Starting at the center, the depth of the water is measured every 25 feet and recorded in the table (a) Use the regression capabilities of a graphing utility to find a quadratic model for the depths recorded in the table. Use the graphing utility to plot the depths and graph the model. (b) Use the integration capabilities of a graphing utility and the model in part (a) to approximate the volume of water in the pond. (c) Use the result of part (b) to approximate the number of gallons of water in the pond.

0 25 50
20
Depth 20
19
19
18
16
14
12
75
100
125
10
Depth| 17
15
14
2-
50 175 200
150
50
100
150
200
Distance from center
Depth
10
(in feet)
Depth (in feet)
Transcribed Image Text:0 25 50 20 Depth 20 19 19 18 16 14 12 75 100 125 10 Depth| 17 15 14 2- 50 175 200 150 50 100 150 200 Distance from center Depth 10 (in feet) Depth (in feet)
Expert Solution
Step 1

The given data,

x 0 25 50 75 100 125 150 175 200
Depth 20 19 19 17 15 14 10 6 0

We have to find,

(a) The regression equation for a quadratic model for the depths recorded in the table.

(b) Using the integration capabilities of a graphing utility and the model in part (a) we have to approximate the volume of water in the pond.

(c) Use the result of part (b) to approximate the number of gallons of water in the pond.

Step 2

a)

The given data,

x 0 25 50 75 100 125 150 175 200
Depth 20 19 19 17 15 14 10 6 0

Using the regression calculator,

The quadratic model for the depths is recorded in the table is d=-0.00056x2+0.01887x+19.393939.

Graph of the depths and the quadratic model.

Advanced Math homework question answer, step 2, image 1

Step 3

b)

The formula for the volume of water in the pond is,

V=2πabpxhxdx.

Here px=x, hx=d, a=0 and b=200.

Now,

V=2π0200x-0.00056x2+0.01887x+19.393939dx

Solve this integral we get

V1345850.6

The volume of water in the pond is 1345850.6 ft3.

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