. Eukaryotic genes can be introduced into bacteria by recombinant DNA techniques. If the ntroduced gene encodes a protein that glycolysis enzyme–then expression of the eukaryotic gene may produce a protein that functions in Ehe bacterial cell. also found in bacteria-for example, a universally used In an experiment, the entire mouse gene for a glycolysis enzyme, including its promoter, coding regions and termination sequence, is introduced into an E. coli cell that has a mutant gono for th

Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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1. Eukaryotic genes can be introduced into bacteria by recombinant DNA techniques. If the
introduced gene encodes a protein that is also found in bacteria-for example, a universally used
glycolysis enzyme–then expression of the eukaryotic gene may produce a protein that functions in
the bacterial cell.
In an experiment, the entire mouse gene for a glycolysis enzyme, including its promoter, coding
regions and termination sequence, is introduced into an E. coli cell that has a mutant gene for the
bacterial version of the same enzyme. Even though the mouse enzyme should function in the
bactèrial cell and restore the cell's ability to perform glycolysis, it does not.
Provide a possible reason why this experiment does not work and propose a solution to overcome
the problem you suggest.
Transcribed Image Text:1. Eukaryotic genes can be introduced into bacteria by recombinant DNA techniques. If the introduced gene encodes a protein that is also found in bacteria-for example, a universally used glycolysis enzyme–then expression of the eukaryotic gene may produce a protein that functions in the bacterial cell. In an experiment, the entire mouse gene for a glycolysis enzyme, including its promoter, coding regions and termination sequence, is introduced into an E. coli cell that has a mutant gene for the bacterial version of the same enzyme. Even though the mouse enzyme should function in the bactèrial cell and restore the cell's ability to perform glycolysis, it does not. Provide a possible reason why this experiment does not work and propose a solution to overcome the problem you suggest.
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