. A steel cooling spine of cross-sectional 1.2" x 1.2" and length L = 8" extends from a wall maintained at temperature T = 100 °F (see below picture). . The thermal conductivity of steel material is k = 6.9034e-3 BTU/s.ft. °F. . The surface convection coefficient between the & surrounding air is h=2.778e-4 BTU/s.ft² °F. . The air temperature is T₁ = 0 °F and the tip of the spine is insulated. . Run ANSYS steady state thermal analysis.
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- 1. A wall is made up of brick of thermal conductivity 1.0 W/(m.K),230 mm thick .It is lined on the inner face with plaster of thermal conductivity of 0.4 W/(m.K),and of thickness 10 mm .If a temperature difference of 30K is maintained between the two faces .What is the heat flow per unit area of wall?A boiler furnace wall must have a heat loss no greater than 700 Btu/hr~ft2 and is madeof a material with a thermal conductivity of 0.60 Btu/hr~ft~F. The inner wall surfacetemperature is '2000°F, and the outer surface temperature is 800°F. What wall thick~ness is required?Made-Up Problem (from class): 20.00 °C along its complete length. One end 60.00 °C, while the other end of the rod is placed in contact with a cold reservoir at T, = 20.00 °C, thus setting up a thermal gradient along the length of the rod. Using An aluminum rod of length L = 1.000m is at an initial temperature of T of the aluminum rod is placed in contact with a hot reservoir at TH the methods outlined in lecture as "Made-up Problem", determine the extension of the aluminum rod under these conditions.
- Furnace walls are lined by 3 layers: firebrick with a thickness of 6 in (k=0.95 Btu/h.ft. F), insulating brick (k-0.4 Btu/h.ft.°F) and common brick (k=0.8 Btu /h.ft.°F) Firebrick inlet temperature, T₁ = 1800°F, maximum insulating brick temperature, T₂ = 1720°F and T3 = 280°F. 1. Calculate the thickness of the insulating brick layer. 2. If the common brick is 9 in, calculate the exit temperature.c) A steel pipe of 100 mm bore, and 10 mm bore thickness, carrying dry saturated steam at 28 bars, is insulated with a 40 mm layer of moulded insulation. This insulation in turn is insulated with a 60 mm layer of felt. The atmospheric temperature is 15 °C. Calculate: (i) the rate of heat loss by the steam per metre pipe length. (ii) the temperature of the outside Dimensions in mm surface.zzzzzzz h₂-15 W/m²K Steel k₁=50 W/mK AVALEHT Ø100 1₂ " Steam 28 bar h-550 W/m²K, Inner heat transfer coefficient = 550 W/m² K Outer heat transfer coefficient = 15 W/m² K Thermal conductivity of steel = 50 W/m K Thermal conductivity of felt = 0.07 W/m K Moulded insulation Felt Moulded insulation K₂=0.09 W/mK Thermal conductivity of moulded insulation = 0.09 W/m 40 10. A 60 15°C Felt K₁=0.07 W/mK zzzzzzzzHEAT TRANSFER: A thick-walled nuclear coolant pipe (k = 12.5 Btu/hr-ft-°F) with 10 in. inside diameter and 12 in. outside diameter is covered with a 3 in. layer of asbestos insulation (k 0.14 = Btu/hr-ft-°F). If the inside wall temperature of the pipe is maintained at 550°F, (a) calculate the heat loss per foot of length. The outside temperature is 100°F. (b) Find the interface temperature between the pipe and the insulation.
- What is the rate of heat transfer through a piece of Celotex 3 ft by 8 ft by 1 in. in thickness, if the temp of one surface is 80°F and of the other side is 60°F? thermal conductivity of Celotex in AES = 0.028. Pls determine the temperature gradient and the direction of the heat transfer as well.Problem 4 A cork board (k = 0.039W/m K) 3 cm thick is exposed to air with an average temperature T.. = 30°C with a convection heat transfer coefficient, h = 25 W/m².K. The other surface of the board is held at a constant temperature of 15°C. A volumetric heat generation of 5 W/m³ is occurring inside the wall. Assuming one dimensional conduction, write the governing equation and express the boundary conditions for the wall. (solve the equation is not required) ProblomExample:- Let us represent the body's surface tissue as layer of thickness X1=5 cm which has a thermal conductivity K,= 0.59 J/m.s. ºC . This is surrounded by a layer of tissues fat of thickness X,=2 cm with K,=0.21 J/m.s. °C .The body's interior is at temperature T¡=37°C and the skin temperature is T,=33.5°C .What is the heat loss per unit area?
- Homework O H.W. 1: The walls of a refrigerator are typically constructed by sandwiching a layer of insulation between sheet metal panels. Consider a wall made from fiberglass insulation of thermal conductivity k; = 0.046 W/m.K and thickness L, = 50 mm and steel panels, each of thermal conductivity k, = 60 W/m.K and thickness L, = 3 mm. If the wall separates refrigerated air at T = 4 C from ambient air at T,. = 25 C, what is the heat gain per unit surface area? Coefficients associated with natural convection at the inner and outer surfaces may be approximated as h, = h, = 5 W/m?.K. %3D %3D L; = 0.050 m K K Lo = 0.003 m Refrigerated air Ambient air Too.i = 4°C hi = 5 W/m2-K To,o = 25°C ho = 5 W/m2-K %3D Panel (2) kp = 60 W/m-K Insulation k; = 0.046 W/m-K 22 Warith Alanbiyaa (Dr. ALI M) Heat Transfer Page 11 of2. In determining the thermal conductivity of a plateflat insulator, the temperature was measured on both sides of the 25 mm thick plate and gave the results of 318.4 K and 303.2 K. FluxThe measured heat is 35.1 W.m-2. Illustrate the problem in a simple schematic/drawing, then calculate the thermal conductivity inbtu/h.ft.oF and in W/m.K! (0.033 ; 0.058) 3. A coil-shaped cooling pipe is made of SS-304 material. This pipe is 1 ft long, 0.4 inch outside diameter, and inch inside diameter. This coil cooling pipe is used to cool the water in the bath. The temperature of the inner coil pipe is 40oF while the outer coil in contact with water is 80oF. The thermal conductivity of SS-304 is a function of temperature where k(T) = 7.75 + (7.78 x 10-3).T where k is in Btu/h.ft.oF and T is in oF. Calculate the rate of heat dissipation in watts! (1287.7)4. A spherical steel reaction vessel has an outer radius of 2.0 m and is covered in lagging 250mm thick. The thermal conductivity of the lagging is 0.4 W/m K. The temperature at the surface of the steel is 340⸰C and the surface temperature of the lagging is 45 ⸰ Calculate the heat loss.Thermal Conductivity;k=385 W/mK