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Catalase Activity Lab Results

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Statement of the Problem:
The heat used on the chicken liver helped with the observation to see how the water, hydrogen peroxide, and hydrochloric acid worked.
How does the chicken liver start to dissolve in the hydrogen peroxide and hydrochloric acid?
The way our group had tested this was by using the pieces of chicken liver and 10 ml of water, hydrogen peroxide, and hydrochloric acid in a container with using the probe to heat up the 3 pieces of raw chicken liver and the 1 boiled chicken liver.

Variables:
The independent variable of this lab is heat which the point for water to boil is 100 degrees celsius. The pH levels were 10 mL of HCl for the lab.
The dependent variable of this lab is the catalase activity 02.. Throughout the lab I …show more content…

The control for the experiment was the raw liver in the hydrogen peroxide.
Hypothesis:
If heat is added to the livers, then they will have a larger reading than if there was no heat added to the livers at all.
If pH is lower than the liver, then it would have a smaller reading the rest of the experiment.
Materials:
Four pieces of chicken liver
10 mL graduated cylinder
Vernier Oxygen Probe
Nalgene Bottle that comes with the Oxygen Probe
Hydrogen Peroxide
Counter for holding the 4 pieces of liver (Glass Culture Dish)
Procedure:
Read the entire lab. Identify the information to put in a data table. Create a data table that can record the data that will collect the information in this lab. Start up the logger pro program on your computer. You need to click on File -> Open -> Biology with Vernier -> Experiment 6A “Enzyme (O2)” to open the correct experiment. Pour 10 mL of water from a sink into the Nalgene bottle. Drop a small piece of liver into the bottle that contains the water. Place the Oxygen probe in the bottle and press the green collect button. Press the stop button after 100 seconds. The time will be listed on the vertical axis of the graph. Click the “Linear Fit button", to perform a linear regression. A floating

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