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Experimenting With Enzymes Exploration Lab

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Experimenting with Enzymes Exploration Lab
Ali Al-Husseini
IB Biology 5th Period

Exploration-

How does increasing the substrate concentration of Hydrogen Peroxide from 0 to 15% at 3% intervals affect the enzyme catalase in yeast?

In this lab, the independent variable would be the hydrogen peroxide concentration. The concentrations used in this lab will be 0%, 3%, 6%, 9%, 12%, and 15% concentration.
The dependent variable is the rate or reaction which is the actual time required for the catalase soaked paper to float.

The controlled variables are the time required for the paper to be soaked inside the catalase, the actual size of the beakers, the same stopwatch used for all the concentrations, the amount …show more content…

Background Research: An enzyme is a catalyst. More specifically, they are macromolecular biological catalysts. Enzymes bind with a substrate molecule at the enzymes’ active site. By lowering the required activation energy, enzymes allow reactions to happen faster. There is no change to the enzyme as a result of the reaction; consequentially, enzymes allow chemical reactions to speed up. Hydrogen peroxide is the resulting product that is produced by the body’s chemical reactions. Pretty much all living things contain Common Enzymes which are exposed to oxygen and is known as Catalase. The molecules that are a result of a catalyzing reaction, in which an enzyme will bind, is the enzymes substrates. As the catalase interacts with hydrogen peroxide, its substrate, it breaks down into oxygen and water. This is demonstrated by
2H2O2 2H2O + O2 (pp.25)
The reaction is reliant on the substrate concentration. Yeast is a common place to find the enzyme catalase.

There is a method known as “Floating disc method” often used to find the reaction rate of the enzyme. This is when a little amount of paper, specifically filter paper, is first soaked in yeast, in then put in the substrate solution. At this point, the catalase will begin to catalyze the hydrogen peroxide to result in water and oxygen. The paper will begin to float because the oxygen will remain sticking to the other oxygen. The reaction rate can then be solved by finding the amount of time required for the

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