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Business Level 3 Unit 21 D1

Satisfactory Essays

Let V be the sample space Number of Cards in Pack = 52 Number of Kings / Queens in Pack = 4 Then, n(V) = 〖52C〗_2 = ((52 ×51)/(2 ×1)) = 2652/2 = 1326 Let S = event of getting 2 kings out of 4. There are 4 kings in the pack of cards and we assume the event S as the event of getting 2 cards of kings out of 4.Therefore, n(S) = 〖4C〗_2 = ((4 ×3)/(2 ×1)) = 12/2 = 6 Therefore, P(S) = (n(S))/(n(V)) = 6/1326 = 1/221 = 0.004525 Therefore, Probability of Drawing Both Kings is 0.004525. Similarly, Let A be the event of getting both cards as queen. There are 4 queens in the pack of cards and we assume the event A as the

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