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7.03 Lab Ph Essay

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Procedure:
Part I: Titration with an Indicator
1. Fill the 50-milliliter buret with a 0.25 molar NaOH solution.
2. Record volume.
3. Measure out between 20 milliliters and 40 milliliters of the unknown HCl solution.
4. Record volume.
5. The amount of unknown HCl is then added to the 100-milliliter Erlenmeyer flask.
6. Add two drops of the indicator, phenolphthalein, to the acid in the flask.
7. Using the slider on the right hand side, add NaOH to the HCl in the Erlenmeyer flask (This action is known as titrate). Add the indicator until the color of the indicator turns a light shade of pink.
8. Record the volume.
9. If you went too far past the end point, please record the results of your trial. Include all sets of data in …show more content…

Determine the volume of sodium hydroxide added to the flask from the buret.
30 mL of NaOH 2. Calculate the molarity of the Hydrochloric acid in the flask. You may refer to the Titration demo at the beginning of the honors lesson, just above the Virtual Lab to see sample calculations.
30 Ml HCl * 1L * 1 mol HCl ----------- --------------- = 0.03 mol HCl 1000 mL 1 L

Conclusion: 1. Describe the graph of pH values over the course of the reaction in Part II. Was the change in pH consistent over the course of the reaction? Do your best to explain the reason for the shape of the pH curve in your own words:

Yes, the change in the pH curve increases for each trial, and in consistent in its growth. I believe this was because of the increased amount of NaOH.

2. Why is it important to stir the solution in the flask as you add titrant from the buret?

So it dispenses it evenly. This allows you to get a more accurate reading because it would fully concentrate/mix together.

3. If a student did not remove all of the bubbles from inside the buret before reading the initial volume and beginning the titration, will this cause the calculated concentration of the hydrochloric acid determined from that trial to be higher or lower than the actual concentration? Explain your answer in complete

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