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Nt1310 Unit 6 Lab Report

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Section: Lab: 5 Program: PCLTN Performed: 28 November, 2014 Submitted: 5 December, 2014 …show more content…

It means SPEC – 20 is now calibrate. Prepare standard solution #1, Take 1 ml sub stock solution from the 100 ml beaker and then put into 25 ml volumetric flask with the help of 10ml graduate pipette. Add RO water to the 25 ml volumetric flask up to the mark. Put stopper on the flask and shake it properly. Measure the % Transmittance of standard solution 1 by using SPEC -20. Repeat steps 6 -8 for standard solution 2, 3, 4 and 5. Record the value of % Transmittance in lab notebook. Observations: Part B Standard Solution Volume of Sub stock Solution (ml) % Transmittance 1 1.0 ml 79.2 % 2 2.0 ml 65.8 % 3 4.0 ml 45.5 % 4 8.0 ml 20.4 % 5 10.0 ml 12.9 % Figure 1 : % transmittance of Standard Solutions Part D: Unknown samples % Transmittance Unknown A 19.7 % Unknown B 60.3 % Figure 2 : % Transmittance of Unknown Solutions …show more content…

# 1 = (0.0008 g/l)/(350.13 g/mol) = 2.3 × 10-6 moles / l Molarity for sol. # 2 = (0.0016 g/l)/(350.13 g/mol) = 4.6 × 10-6 moles/ l Molarity for sol. # 3 = (0.0032 g/l)/(350.13g/mol) = 9.1 × 10-6 moles/l Molarity for sol . #4 = (0.0064 g/l)/(350.13 g/mol) =1.8 × 10-5 moles/l Molarity for sol. #5 = (0.0080 g/l)/(350.13 g/mol) =2.3 × 10-5 moles/l CALCULATION of Concentration in ppm: Concentration of stock solution in ppm = (0.002g×1000mg )/(1 L ×1g) = 20 mg/L 1mg/L = 1ppm, so 20 mg/L = 20 ppm Concentration of Standard solution # 1 = (0.0008g×1000mg )/(1 L ×1g) = 0.8 mg/L = 0.8 ppm Concentration of Standard solution #2 = (0.0016g×1000mg )/(1 L ×1g) = 1.6 mg/L = 1.6 ppm Concentration of standard solution # 3 = (0.0032g×1000mg )/(1 L ×1g) = 3.2

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