The velocities of the blocks of ice after the collision
Answer to Problem 58QAP
The velocities of the ice blocks after the collision are 5 m/s and 9 m/s.
Explanation of Solution
Given info:
A 10 kg block of ice is sliding due east at 8 m/s when it collides elastically with a 6 kg block of ice that is sliding in the same direction at 4 m/s.
Formula used:
Using the formula, conservation of linear momentum
Here,
Also, for elastic collision
Here, e is coefficient of restitution is 1 for elastic collision.
Calculation:
We have,
Substituting the given values in equ.(1), we get
Now from equation(2)
From equations (3) and (4), we get
Substituting in equation (4), we get
Conclusion:
Thus, the velocities of the ice blocks after the collision are 5 m/s and 9 m/s.
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