Modern Database Management (12th Edition)
12th Edition
ISBN: 9780133544619
Author: Jeffrey A. Hoffer, Ramesh Venkataraman, Heikki Topi
Publisher: PEARSON
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Chapter 6, Problem 6.64PAE
Program Plan Intro
SQL query to show the product line ID and the average standard price for all the products in product line.
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Chapter 6 Solutions
Modern Database Management (12th Edition)
Ch. 6 - Prob. 6.1RQCh. 6 - Prob. 6.2RQCh. 6 - Contrast the following terms: a. base table; view...Ch. 6 - Prob. 6.4RQCh. 6 - Prob. 6.5RQCh. 6 - Prob. 6.6RQCh. 6 - List six potential benefits of achieving an SQL...Ch. 6 - Prob. 6.8RQCh. 6 - Distinguish among data definition commands, data...Ch. 6 - Prob. 6.10RQ
Ch. 6 - Prob. 6.11RQCh. 6 - Prob. 6.12RQCh. 6 - Prob. 6.13RQCh. 6 - Drawing on material covered in prior chapters,...Ch. 6 - Explain and provide at least one example Of how to...Ch. 6 - Prob. 6.16RQCh. 6 - What is the difference between COUNT, COUNT...Ch. 6 - What is the evaluation order for the Boolean...Ch. 6 - If an SQL statement includes a GROUP BY clause,...Ch. 6 - Prob. 6.20RQCh. 6 - Prob. 6.21RQCh. 6 - Prob. 6.22RQCh. 6 - Explain why SQL is called a set-oriented language.Ch. 6 - When would the use of the LIKE key word with the...Ch. 6 - Prob. 6.25RQCh. 6 - Prob. 6.26RQCh. 6 - In what order are the clauses of an SQL statement...Ch. 6 - Within which clauses of an SQL statement can a...Ch. 6 - Prob. 6.29RQCh. 6 - Prob. 6.30RQCh. 6 - Prob. 6.31RQCh. 6 - Explain the difference between the WHERE and...Ch. 6 - Prob. 6.33RQCh. 6 - Prob. 6.34PAECh. 6 - Are based on the class scheduling 3NF relations...Ch. 6 - Prob. 6.36PAECh. 6 - Are based on the class scheduling 3NF relations...Ch. 6 - Are based on the class scheduling 3NF relations...Ch. 6 - Are based on the class scheduling 3NF relations...Ch. 6 - Prob. 6.40PAECh. 6 - Are based on the class scheduling 3NF relations...Ch. 6 - Prob. 6.42PAECh. 6 - Prob. 6.43PAECh. 6 - Are based on the class scheduling 3NF relations...Ch. 6 - Prob. 6.45PAECh. 6 - Prob. 6.46PAECh. 6 - Prob. 6.47PAECh. 6 - Prob. 6.48PAECh. 6 - Prob. 6.49PAECh. 6 - Prob. 6.50PAECh. 6 - Prob. 6.51PAECh. 6 - Prob. 6.52PAECh. 6 - Prob. 6.53PAECh. 6 - Modify the Product_T table by adding an attribute...Ch. 6 - Prob. 6.55PAECh. 6 - Add an order to the Order_T table and include a...Ch. 6 - Use the Pine Valley database to answer the...Ch. 6 - Prob. 6.58PAECh. 6 - Prob. 6.59PAECh. 6 - Prob. 6.60PAECh. 6 - Prob. 6.61PAECh. 6 - Prob. 6.62PAECh. 6 - Prob. 6.63PAECh. 6 - Prob. 6.64PAECh. 6 - Prob. 6.65PAECh. 6 - Prob. 6.66PAECh. 6 - Prob. 6.67PAECh. 6 - Prob. 6.68PAECh. 6 - Prob. 6.69PAECh. 6 - Prob. 6.70PAECh. 6 - Prob. 6.71PAECh. 6 - Prob. 6.72PAECh. 6 - Prob. 6.73PAECh. 6 - Prob. 6.74PAECh. 6 - Prob. 6.75PAECh. 6 - Prob. 6.76PAECh. 6 - Prob. 6.77PAECh. 6 - Prob. 6.78PAECh. 6 - Prob. 6.79PAECh. 6 - Prob. 6.80PAECh. 6 - Prob. 6.81PAECh. 6 - Prob. 6.82PAECh. 6 - Prob. 6.83PAECh. 6 - Prob. 6.84PAECh. 6 - Prob. 6.85PAE
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- Display only the products (name and ID) that have a quantity greater than the average quantity of all products.arrow_forwardFor each customer, list the CustomerID and the total number of orders placed in 2015.arrow_forwardFor each product, show the product ID and the number of orders placed.Show the results in decreasing order based on the number of times the product has been ordered, with NumOrders as the result column.arrow_forward
- Select all the staff full names with the customer full names of the consignments they have worked on. Include staff that have not worked on any consignmentsarrow_forwardDisplay the territory ID and the number of salespersons in the territory for all territories that have more than one salesperson. Label the number of salespersons NumSalesPersonsarrow_forwardList all vendors with their address(city, state,zipcode) for all the vendors who have credited account (credit total>0)) Hint:Vendors & Invoices tables with credit total column WHERE vendors.vendor id = invoices.vendor id AND CREDIT_TOTAL>0; %3Darrow_forward
- Examine this product table's column definitions:pid number primary keypname varchar2(50)You must display column headings as shown:Product_ID Product NameWhich SELECT statement does this? SELECT pid Product_ID, pname Product Name FROM product; SELECT pid Product_ID, pname "Product Name" FROM product; SELECT pid @Product_ID, pname @"Product Name" FROM product; SELECT pid AS Product_ID, pname AS Product Name FROM productarrow_forwardFor each employee, show their full name and the region name of their departmentarrow_forwardPRODUCTS PID DESC PRICE SID QTY 801 Pencil 3 1 10 802 A4 6 2 15 803 Ballpen 4 2 804 Marker 2 3 20 Display the Product ID, Description, and Quantity (QTY) of all the products in the PRODUCTS table whose PID is from 801 to 802 and whose quantity is less than 15.arrow_forward
- Product_id Product_name Category Mfg_date Exp_Dte Product_price 01 Dairy Milk Choclate Junk 2,Aug, 2019 2aug, 2020 80 02 Lipton Tea Bags Not junk 2,jan 2019 2, jan 2020 160 03 Kurkure junk 2, april 2919 2, april, 2021 30 04 Shezan Juice Junk 3,Aug, 2019 3,aug, 2020 30 06 Olpers Milk Not junk 3,april, 2018 3,april, 2020 350 Canteen_table 1: Write query to create canteen_table. Put check on category values as only “junk” and “Not junk”. Change colum name of product_price to unit_price. Display products manufactured between 1, jan 2019 to 1, May 2019. Display count of only junk food items in canteen_table with alias name as “junk Food Count”. Display Count Of both Junk food and not junk food products whose count is greater then 1.arrow_forwardPRODUCTS PID DESC PRICE SID QTY 801 Pencil 3 1 10 802 A4 6 2 15 803 Ballpen 4 2 804 Marker 2 3 20 SUPPLIERS SID SNAME STYPE LOCATION 1 Lulu DS Salalah 2 C4 DS Saadah 3 Smile WS Awqad Display the maximum price of all the products in PRODUCTS table for each Supplier ID having a maximum price more than 5.arrow_forward
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