Introduction to Electrodynamics
4th Edition
ISBN: 9781108420419
Author: David J. Griffiths
Publisher: Cambridge University Press
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Question
Chapter 4.4, Problem 4.18P
(a)
To determine
To Find: The expression of electric displacement
(b)
To determine
To Find: The expression of the electric field
(c)
To determine
To Find: The expression of the polarization
(d)
To determine
To Find: The expression of potential difference between the plates.
(e)
To determine
To Find: The expression of the location and the amount of all bound charges.
(f)
To determine
To Find: The expression of the electric field in each slab, using charge (free and bound).
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Problem 3.01. (a) Find the electric field between two plates which are separated along the y-axis Ay = 6.00
mm, where the bottom plate has a potential V₂ = 150. mV and the top plate has a potential V₁ = 5.00 mV.
(b) What is the potential at a distance Ay' = 2.00 um from the bottom plate?
The space between the plates of a parallel-plate capacitor (Fig. 4.24) is filled with
two slabs of linear dielectric material. Each slab has thickness a, so the total distance
between the plates is 2a. Slab-1 has dielectric constant of 2 and slab-2 has a dielectric
constant of 1.5. With the area of each of the top and bottom conducting plates is
much greater than a?, we can assume the the surface charge densities +o and -o on
the top and bottom plates is uniform.
(a) Find the electric displacement D in each slab.
(b) Find the electric field E in each slab.
(c) Find the potential difference between the plates.
(d) Find the locations and amounts of all bound charge.
(e) Based on the values of bound charge, recalculate E and verify your answer from
(b).
(f) How do your results relate to the formula for the addition of two series capacitors?
[
Q.3
A capacitor has orthogonal plates of length a and width b. The distance between the plates is
h<< a, b. The capacitor has a charge Q. The space between the plates is initially vacuum and we
insert slowly a slab of dielectric material as of dielectric constant & as shown in figure. What is the
force that is exerted on the slab when it has entered a distance x inside the capacitor?
a
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