(a)
The wavelength and direction of the propagating wave.
(a)
Answer to Problem 46P
The wavelength of the wave is
Explanation of Solution
Given:
The frequency is
The magnetic is
Formula used:
The expression for wavelength is given by,
Calculation:
The wavelength of the wave is calculated as,
Conclusion:
Therefore, the wavelength of the wave is
(b)
The electric field vector.
(b)
Answer to Problem 46P
The electric field vector is
Explanation of Solution
Formula used:
The expression for electric field vector is given by,
The expression for amplitude of electric field is given by,
The expression for angular frequency is given by,
The expression for wave number is given by,
Calculation:
The amplitude of electric field is calculated as,
The angular frequency is calculated as,
The wave number is calculated as,
The electric field vector is calculated as,
Conclusion:
Therefore, the electric field vector is
(c)
The Poynting vector and intensity of the wave.
(c)
Answer to Problem 46P
The Poynting vector is
Explanation of Solution
Formula used:
The expression for Poynting vector is given by,
The expression for intensity is given by,
Calculation:
The Poynting vector is calculated as,
Further simplify the above,
The intensity of the wave is calculated as,
Conclusion:
Therefore, the Poynting vector is
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Chapter 30 Solutions
Physics for Scientists and Engineers
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