Chapter 3, Problem 77QAP

Interpretation Introduction

(a)

Interpretation:

The element having the smaller molar mass needs to be determined.

Concept introduction:

The number of moles of an atom of element is related to mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass of atom of element in grams and M is molar mass in grams/mol.

In 1 mol of an element the number of atoms is $6.023\times {10}^{23}$ and mass of 1 mol of an element is molar mass thus, mass of $6.023\times {10}^{23}$ of element is molar mass.

Interpretation Introduction

(b)

Interpretation:

The element with more atoms per gram needs to be determined.

Concept introduction:

The number of moles of an atom of element is related to mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass of atom of element in grams and M is molar mass in grams/mol.

In 1 mol of an element the number of atoms is $6.023\times {10}^{23}$ and mass of 1 mol of an element is molar mass thus, mass of $6.023\times {10}^{23}$ of element is molar mass.

Interpretation Introduction

(c)

Interpretation:

The element with more atoms/gram needs to be calculated.

Concept introduction:

The number of moles of an atom of element is related to mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass of atom of element in grams and M is molar mass in grams/mol.

In 1 mol of an element the number of atoms is $6.023\times {10}^{23}$ and mass of 1 mol of an element is molar mass thus, mass of $6.023\times {10}^{23}$ of element is molar mass.

Interpretation Introduction

(d)

Interpretation:

The element with more atoms per mole needs to be determined.

Concept introduction:

The number of moles of an atom of element is related to mass and molar mass as follows:

$n=\frac{m}{M}$

Here, m is mass of atom of element in grams and M is molar mass in grams/mol.

In 1 mol of an element the number of atoms is $6.023\times {10}^{23}$ and mass of 1 mol of an element is molar mass thus, mass of $6.023\times {10}^{23}$ of element is molar mass.