Concept explainers
(a)
The image distance, height, type and orientation of the image
Answer to Problem 49QAP
Image distance
Image height
Type of image = Real
Orientation of the image = Inverted
Explanation of Solution
Given info:
Distance to the object from the mirror =
Radius of the mirror =
Height of the object =
Formula used:
Calculation:
Conclusion:
Image distance
Image height
Type of image = Real
Orientation of the image = Inverted
(b)
The image distance, height, type and orientation of the image
Answer to Problem 49QAP
Image distance
Image height
Type of image = Real
Orientation of the image = Inverted
Explanation of Solution
Given info:
Distance to the object from the mirror =
Radius of the mirror =
Height of the object =
Formula used:
Calculation:
Conclusion:
Image distance
Image height
Type of image = Real
Orientation of the image = Inverted
(c)
The image distance, height, type and orientation of the image
Answer to Problem 49QAP
Image distance
Image height
Type of image = Real
Orientation of the image = Inverted
Explanation of Solution
Given info:
Distance to the object from the mirror =
Radius of the mirror =
Height of the object =
Formula used:
Calculation:
Conclusion:
Image distance
Image height
Type of image = Real
Orientation of the image = Inverted
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Chapter 24 Solutions
COLLEGE PHYSICS
- An object is placed at a distance of 10.0 cm from a convex mirror of focal length 5.00 cm. Which of the following is the image formed? • di = +3.33 cm and M = -0.333 O di = 10.0 cm and M = -1.00 O di = -3.33 cm and M = +0.333 O dj = -10.0 cm and M= +1.00arrow_forward• A concave mirror produces a virtual image that is three times as tallas the object. (a) If the object is 16 cm in front of the mirror, what is theimage distance? (b) What is the focal length of this mirror?arrow_forward•• A certain telescope uses a concave spherical mirror that has a radius equal to 8.0 m. Find the location and diameter of the image of the moon formed by this mirror. The moon has a diameter of 3.5 X 10°m and is 3.8 x 10* m from Earth. 31arrow_forward
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- • (a) Use a ray diagram to determine the approximate location ofthe image produced by a concave lens when the object is at a distance 2∙ ƒ ∙ from the lens. (b) Is the image upright or inverted? (c) Isthe image real or virtual? Explain.arrow_forward• A mirrored-glass gazing globe in a garden is 31.9 cm in diameter.What is the focal length of the globe?arrow_forwardMath is not required, however you can use it to help with yoursolution. • You are only required to draw the position of the FINAL IMAGE given the system of lenses bellow. Use the following information: Focal length of biconvex lens=25 cm and focal length of the biconcave length =-10 cm Object 1.00 m 35 cm Hint: Find or estimatehow far the image from the lens is from the biconcave lens. Use thatto graph the optical rays between both lenses to get the FINAL IMAGE.arrow_forward
- Asaparrow_forward(c) 55 cm cm 308 cm FIGURE 3 A thin hemispherical clear plastic bowl of radius 55 cm is placed in a tank filled with water (nwater = 1.33). The base of the bowl sinks to a depth of 8 cm and the water level rises to a height of 308 cm as shown in FIGURE 3. An object at the bottom of the tank is viewed vertically from above the bowl. (i) Calculate the image distance from the base of the bowl. (ii) Is the image virtual or real? Justify your answer. The radius of curvature of a bi-convex lens is 24 cm. The refractive index of the lens is 1.54. Calculate the focal length of the lens. (d)arrow_forwardDraw the ray diagram of this problem An object is placed 50 cm in front of a concave mirror of 60 cm radius. Determine the (a) focal length, (b) image distance, (c) linear magnification, (d) object size if the image produced was 3 cm. (e) define the image produced (f) ray diagram.arrow_forward
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