How does the voltmeter reading compare to the potential difference across the electrodes? Explain. If the sliding lead from electrode A were connected at point C along the resistor, would the voltmeter reading be positive, negative , or zero ? Explain. ( Hint: Imagine disconnecting the ammeter and evacuated tube from the rest of the circuit, and answering the same question.) How would you adjust the sliding connection from electrode A in order to make the potential difference across the electrodes ( △ V B A = V A − V B ) become (i) more and more positive? (ii) more and more negative? Explain.

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Answer 1

Textbook Question

Chapter 14.2, Problem 1aT

How does the voltmeter reading compare to the potential difference across the electrodes? Explain.

If the sliding lead from electrode A were connected at point C along the resistor, would the voltmeter reading be positive, negative, or zero? Explain.

Chapter 14.2, Problem 1aT, How does the voltmeter reading compare to the potential difference across the electrodes? Explain.
(Hint: Imagine disconnecting the ammeter and evacuated tube from the rest of the circuit, and answering the same question.)

How would you adjust the sliding connection from electrode A in order to make the potential difference across the electrodes ( △ V B A = V A − V B ) become (i) more and more positive? (ii) more and more negative? Explain.

Expert Solution & Answer

To determine

The potential difference reading in the voltmeter.

Voltmeter reading positive, negative or zero.

To adjustment to be made for the Voltmeter reading as positive and negative.

Answer to Problem 1aT

The potential across the electrodes is equal to the potential difference reading in the voltmeter.

Voltmeter reading will be positive.

By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Explanation of Solution

Introduction:

Photoelectric effect: Electrons from a metal surface are ejected when a light of an appropriate frequency is incident on it.The ejected electrons are called photoelectrons and the whole phenomenon is called photoelectric effect. This effect was explained by The Albert Einstein.

Figure 1 shows the circuit diagram to study the Photoelectric effect (PE).

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 1

Figure 1: Set up to study photoelectric effect

A monochromatic is incident on one of the electrodes ‘b’ . Electron bonded to a metal requires a minimum energy just to leave the surface of metal is called binding energy of electron, also known as work function of the electron and denoted as φ . If the energy ‘E’ of the incident wave is adequate enough to eject the electron from the electrode ‘b’ , these electrons are attracted towards the electrode ‘a’which is connected to the positive terminal of the of the battery. The voltmeter is connected parallel to the plates of the electrodes. Hence, the potential across the electrodes is equal to the potential difference reading in the voltmeter which depends on the battery connected to the circuit.

Current is flowing from positive to negative terminal of the battery (shown as red arrows in Figure 1).Therefore, the voltmeter will show the potential across electrode positive as electrons are flowing from high potential to lower potential.

Figure 2 shows the circuit diagram to study the Photoelectric effect (PE). In order to obtain the positive potentialdifference, read by voltmeter, figure 2(1) is applicable, as the electrode ‘b’ exposed to light is connected to negative terminal and other electrode ‘a’to the positive terminal of the battery. To make it more positive, one need to increase the potential of the variable battery that will make the electrode ‘a’more positive, hence will result in more positive potential across the electrodes.

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 2

Figure 2: Set up to study photoelectric effect

In order to obtain the negative potential difference,read by voltmeter, figure 2(2) is applicable, as the electrode ‘b’ exposed to light is connected to positive terminal and other electrode ‘a’to the negative terminal of the battery.

Conclusion:

The potential across the electrodes is equal to the potential difference reading in the voltmeter.Voltmeter reading will be positive.By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

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Students have asked these similar questions

Three resistors having resistances of 4.0 Ω, 6.0 Ω, and 10.0 Ω are now connected in series. If the combination is connected to an ideal 12-V. What is the total resistance of the circuit? What is the current through each resistor? What is the voltage drop across each resistor? What is the power dissipated by the 6.0 Ω resistor? Clearly state the formulae you’re using and what your letters/symbols mean.

Three resistors having resistances of 4.0 Ω, 6.0 Ω, and 10.0 Ω are connected in parallel. If the combination is connected to an ideal 12-V. What is the total resistance of the circuit? What is the current through each resistor? What is the power dissipated by the 6.0 Ω resistor? Clearly state the formulae you’re using and what your letters/symbols mean.

The diagram at the right shows two identical resistors - R1 and R2 - placed in a circuit with a 12-Volt battery. If a third resistor (R3), identical to the other two is added in series with the first two, then theelectric potential difference (voltage drop) across each of the three individual resistors will... A. Decrease B. Increase C. Remain the same

Answer 2

Textbook Question

Chapter 14.2, Problem 1aT

How does the voltmeter reading compare to the potential difference across the electrodes? Explain.

If the sliding lead from electrode A were connected at point C along the resistor, would the voltmeter reading be positive, negative, or zero? Explain.

Chapter 14.2, Problem 1aT, How does the voltmeter reading compare to the potential difference across the electrodes? Explain.
(Hint: Imagine disconnecting the ammeter and evacuated tube from the rest of the circuit, and answering the same question.)

How would you adjust the sliding connection from electrode A in order to make the potential difference across the electrodes ( △ V B A = V A − V B ) become (i) more and more positive? (ii) more and more negative? Explain.

Expert Solution & Answer

To determine

The potential difference reading in the voltmeter.

Voltmeter reading positive, negative or zero.

To adjustment to be made for the Voltmeter reading as positive and negative.

Answer to Problem 1aT

The potential across the electrodes is equal to the potential difference reading in the voltmeter.

Voltmeter reading will be positive.

By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Explanation of Solution

Introduction:

Photoelectric effect: Electrons from a metal surface are ejected when a light of an appropriate frequency is incident on it.The ejected electrons are called photoelectrons and the whole phenomenon is called photoelectric effect. This effect was explained by The Albert Einstein.

Figure 1 shows the circuit diagram to study the Photoelectric effect (PE).

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 1

Figure 1: Set up to study photoelectric effect

A monochromatic is incident on one of the electrodes ‘b’ . Electron bonded to a metal requires a minimum energy just to leave the surface of metal is called binding energy of electron, also known as work function of the electron and denoted as φ . If the energy ‘E’ of the incident wave is adequate enough to eject the electron from the electrode ‘b’ , these electrons are attracted towards the electrode ‘a’which is connected to the positive terminal of the of the battery. The voltmeter is connected parallel to the plates of the electrodes. Hence, the potential across the electrodes is equal to the potential difference reading in the voltmeter which depends on the battery connected to the circuit.

Current is flowing from positive to negative terminal of the battery (shown as red arrows in Figure 1).Therefore, the voltmeter will show the potential across electrode positive as electrons are flowing from high potential to lower potential.

Figure 2 shows the circuit diagram to study the Photoelectric effect (PE). In order to obtain the positive potentialdifference, read by voltmeter, figure 2(1) is applicable, as the electrode ‘b’ exposed to light is connected to negative terminal and other electrode ‘a’to the positive terminal of the battery. To make it more positive, one need to increase the potential of the variable battery that will make the electrode ‘a’more positive, hence will result in more positive potential across the electrodes.

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 2

Figure 2: Set up to study photoelectric effect

In order to obtain the negative potential difference,read by voltmeter, figure 2(2) is applicable, as the electrode ‘b’ exposed to light is connected to positive terminal and other electrode ‘a’to the negative terminal of the battery.

Conclusion:

The potential across the electrodes is equal to the potential difference reading in the voltmeter.Voltmeter reading will be positive.By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 14.2, Problem 1aT

How does the voltmeter reading compare to the potential difference across the electrodes? Explain.

If the sliding lead from electrode A were connected at point C along the resistor, would the voltmeter reading be positive, negative, or zero? Explain.

Chapter 14.2, Problem 1aT, How does the voltmeter reading compare to the potential difference across the electrodes? Explain.
(Hint: Imagine disconnecting the ammeter and evacuated tube from the rest of the circuit, and answering the same question.)

How would you adjust the sliding connection from electrode A in order to make the potential difference across the electrodes ( △ V B A = V A − V B ) become (i) more and more positive? (ii) more and more negative? Explain.

Expert Solution & Answer

To determine

The potential difference reading in the voltmeter.

Voltmeter reading positive, negative or zero.

To adjustment to be made for the Voltmeter reading as positive and negative.

Answer to Problem 1aT

The potential across the electrodes is equal to the potential difference reading in the voltmeter.

Voltmeter reading will be positive.

By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Explanation of Solution

Introduction:

Photoelectric effect: Electrons from a metal surface are ejected when a light of an appropriate frequency is incident on it.The ejected electrons are called photoelectrons and the whole phenomenon is called photoelectric effect. This effect was explained by The Albert Einstein.

Figure 1 shows the circuit diagram to study the Photoelectric effect (PE).

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 1

Figure 1: Set up to study photoelectric effect

A monochromatic is incident on one of the electrodes ‘b’ . Electron bonded to a metal requires a minimum energy just to leave the surface of metal is called binding energy of electron, also known as work function of the electron and denoted as φ . If the energy ‘E’ of the incident wave is adequate enough to eject the electron from the electrode ‘b’ , these electrons are attracted towards the electrode ‘a’which is connected to the positive terminal of the of the battery. The voltmeter is connected parallel to the plates of the electrodes. Hence, the potential across the electrodes is equal to the potential difference reading in the voltmeter which depends on the battery connected to the circuit.

Current is flowing from positive to negative terminal of the battery (shown as red arrows in Figure 1).Therefore, the voltmeter will show the potential across electrode positive as electrons are flowing from high potential to lower potential.

Figure 2 shows the circuit diagram to study the Photoelectric effect (PE). In order to obtain the positive potentialdifference, read by voltmeter, figure 2(1) is applicable, as the electrode ‘b’ exposed to light is connected to negative terminal and other electrode ‘a’to the positive terminal of the battery. To make it more positive, one need to increase the potential of the variable battery that will make the electrode ‘a’more positive, hence will result in more positive potential across the electrodes.

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 2

Figure 2: Set up to study photoelectric effect

In order to obtain the negative potential difference,read by voltmeter, figure 2(2) is applicable, as the electrode ‘b’ exposed to light is connected to positive terminal and other electrode ‘a’to the negative terminal of the battery.

Conclusion:

The potential across the electrodes is equal to the potential difference reading in the voltmeter.Voltmeter reading will be positive.By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 14.2, Problem 1aT

How does the voltmeter reading compare to the potential difference across the electrodes? Explain.

If the sliding lead from electrode A were connected at point C along the resistor, would the voltmeter reading be positive, negative, or zero? Explain.

Chapter 14.2, Problem 1aT, How does the voltmeter reading compare to the potential difference across the electrodes? Explain.
(Hint: Imagine disconnecting the ammeter and evacuated tube from the rest of the circuit, and answering the same question.)

How would you adjust the sliding connection from electrode A in order to make the potential difference across the electrodes ( △ V B A = V A − V B ) become (i) more and more positive? (ii) more and more negative? Explain.

Expert Solution & Answer

To determine

The potential difference reading in the voltmeter.

Voltmeter reading positive, negative or zero.

To adjustment to be made for the Voltmeter reading as positive and negative.

Answer to Problem 1aT

The potential across the electrodes is equal to the potential difference reading in the voltmeter.

Voltmeter reading will be positive.

By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Explanation of Solution

Introduction:

Photoelectric effect: Electrons from a metal surface are ejected when a light of an appropriate frequency is incident on it.The ejected electrons are called photoelectrons and the whole phenomenon is called photoelectric effect. This effect was explained by The Albert Einstein.

Figure 1 shows the circuit diagram to study the Photoelectric effect (PE).

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 1

Figure 1: Set up to study photoelectric effect

A monochromatic is incident on one of the electrodes ‘b’ . Electron bonded to a metal requires a minimum energy just to leave the surface of metal is called binding energy of electron, also known as work function of the electron and denoted as φ . If the energy ‘E’ of the incident wave is adequate enough to eject the electron from the electrode ‘b’ , these electrons are attracted towards the electrode ‘a’which is connected to the positive terminal of the of the battery. The voltmeter is connected parallel to the plates of the electrodes. Hence, the potential across the electrodes is equal to the potential difference reading in the voltmeter which depends on the battery connected to the circuit.

Current is flowing from positive to negative terminal of the battery (shown as red arrows in Figure 1).Therefore, the voltmeter will show the potential across electrode positive as electrons are flowing from high potential to lower potential.

Figure 2 shows the circuit diagram to study the Photoelectric effect (PE). In order to obtain the positive potentialdifference, read by voltmeter, figure 2(1) is applicable, as the electrode ‘b’ exposed to light is connected to negative terminal and other electrode ‘a’to the positive terminal of the battery. To make it more positive, one need to increase the potential of the variable battery that will make the electrode ‘a’more positive, hence will result in more positive potential across the electrodes.

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 2

Figure 2: Set up to study photoelectric effect

In order to obtain the negative potential difference,read by voltmeter, figure 2(2) is applicable, as the electrode ‘b’ exposed to light is connected to positive terminal and other electrode ‘a’to the negative terminal of the battery.

Conclusion:

The potential across the electrodes is equal to the potential difference reading in the voltmeter.Voltmeter reading will be positive.By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

The potential difference reading in the voltmeter.

Voltmeter reading positive, negative or zero.

To adjustment to be made for the Voltmeter reading as positive and negative.

Answer to Problem 1aT

The potential across the electrodes is equal to the potential difference reading in the voltmeter.

Voltmeter reading will be positive.

By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Explanation of Solution

Introduction:

Photoelectric effect: Electrons from a metal surface are ejected when a light of an appropriate frequency is incident on it.The ejected electrons are called photoelectrons and the whole phenomenon is called photoelectric effect. This effect was explained by The Albert Einstein.

Figure 1 shows the circuit diagram to study the Photoelectric effect (PE).

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 1

Figure 1: Set up to study photoelectric effect

A monochromatic is incident on one of the electrodes ‘b’ . Electron bonded to a metal requires a minimum energy just to leave the surface of metal is called binding energy of electron, also known as work function of the electron and denoted as φ . If the energy ‘E’ of the incident wave is adequate enough to eject the electron from the electrode ‘b’ , these electrons are attracted towards the electrode ‘a’which is connected to the positive terminal of the of the battery. The voltmeter is connected parallel to the plates of the electrodes. Hence, the potential across the electrodes is equal to the potential difference reading in the voltmeter which depends on the battery connected to the circuit.

Current is flowing from positive to negative terminal of the battery (shown as red arrows in Figure 1).Therefore, the voltmeter will show the potential across electrode positive as electrons are flowing from high potential to lower potential.

Figure 2 shows the circuit diagram to study the Photoelectric effect (PE). In order to obtain the positive potentialdifference, read by voltmeter, figure 2(1) is applicable, as the electrode ‘b’ exposed to light is connected to negative terminal and other electrode ‘a’to the positive terminal of the battery. To make it more positive, one need to increase the potential of the variable battery that will make the electrode ‘a’more positive, hence will result in more positive potential across the electrodes.

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 2

Figure 2: Set up to study photoelectric effect

In order to obtain the negative potential difference,read by voltmeter, figure 2(2) is applicable, as the electrode ‘b’ exposed to light is connected to positive terminal and other electrode ‘a’to the negative terminal of the battery.

Conclusion:

The potential across the electrodes is equal to the potential difference reading in the voltmeter.Voltmeter reading will be positive.By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Answer 8

Expert Solution & Answer

To determine

The potential difference reading in the voltmeter.

Voltmeter reading positive, negative or zero.

To adjustment to be made for the Voltmeter reading as positive and negative.

Answer to Problem 1aT

The potential across the electrodes is equal to the potential difference reading in the voltmeter.

Voltmeter reading will be positive.

By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Explanation of Solution

Introduction:

Photoelectric effect: Electrons from a metal surface are ejected when a light of an appropriate frequency is incident on it.The ejected electrons are called photoelectrons and the whole phenomenon is called photoelectric effect. This effect was explained by The Albert Einstein.

Figure 1 shows the circuit diagram to study the Photoelectric effect (PE).

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 1

Figure 1: Set up to study photoelectric effect

A monochromatic is incident on one of the electrodes ‘b’ . Electron bonded to a metal requires a minimum energy just to leave the surface of metal is called binding energy of electron, also known as work function of the electron and denoted as φ . If the energy ‘E’ of the incident wave is adequate enough to eject the electron from the electrode ‘b’ , these electrons are attracted towards the electrode ‘a’which is connected to the positive terminal of the of the battery. The voltmeter is connected parallel to the plates of the electrodes. Hence, the potential across the electrodes is equal to the potential difference reading in the voltmeter which depends on the battery connected to the circuit.

Current is flowing from positive to negative terminal of the battery (shown as red arrows in Figure 1).Therefore, the voltmeter will show the potential across electrode positive as electrons are flowing from high potential to lower potential.

Figure 2 shows the circuit diagram to study the Photoelectric effect (PE). In order to obtain the positive potentialdifference, read by voltmeter, figure 2(1) is applicable, as the electrode ‘b’ exposed to light is connected to negative terminal and other electrode ‘a’to the positive terminal of the battery. To make it more positive, one need to increase the potential of the variable battery that will make the electrode ‘a’more positive, hence will result in more positive potential across the electrodes.

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 2

Figure 2: Set up to study photoelectric effect

In order to obtain the negative potential difference,read by voltmeter, figure 2(2) is applicable, as the electrode ‘b’ exposed to light is connected to positive terminal and other electrode ‘a’to the negative terminal of the battery.

Conclusion:

The potential across the electrodes is equal to the potential difference reading in the voltmeter.Voltmeter reading will be positive.By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

The potential difference reading in the voltmeter.

Voltmeter reading positive, negative or zero.

To adjustment to be made for the Voltmeter reading as positive and negative.

Answer 12

Answer to Problem 1aT

The potential across the electrodes is equal to the potential difference reading in the voltmeter.

Voltmeter reading will be positive.

By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Answer 13

Explanation of Solution

Introduction:

Photoelectric effect: Electrons from a metal surface are ejected when a light of an appropriate frequency is incident on it.The ejected electrons are called photoelectrons and the whole phenomenon is called photoelectric effect. This effect was explained by The Albert Einstein.

Figure 1 shows the circuit diagram to study the Photoelectric effect (PE).

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 1

Figure 1: Set up to study photoelectric effect

A monochromatic is incident on one of the electrodes ‘b’ . Electron bonded to a metal requires a minimum energy just to leave the surface of metal is called binding energy of electron, also known as work function of the electron and denoted as φ . If the energy ‘E’ of the incident wave is adequate enough to eject the electron from the electrode ‘b’ , these electrons are attracted towards the electrode ‘a’which is connected to the positive terminal of the of the battery. The voltmeter is connected parallel to the plates of the electrodes. Hence, the potential across the electrodes is equal to the potential difference reading in the voltmeter which depends on the battery connected to the circuit.

Current is flowing from positive to negative terminal of the battery (shown as red arrows in Figure 1).Therefore, the voltmeter will show the potential across electrode positive as electrons are flowing from high potential to lower potential.

Figure 2 shows the circuit diagram to study the Photoelectric effect (PE). In order to obtain the positive potentialdifference, read by voltmeter, figure 2(1) is applicable, as the electrode ‘b’ exposed to light is connected to negative terminal and other electrode ‘a’to the positive terminal of the battery. To make it more positive, one need to increase the potential of the variable battery that will make the electrode ‘a’more positive, hence will result in more positive potential across the electrodes.

Tutorials in Introductory Physics, Chapter 14.2, Problem 1aT , additional homework tip 2

Figure 2: Set up to study photoelectric effect

In order to obtain the negative potential difference,read by voltmeter, figure 2(2) is applicable, as the electrode ‘b’ exposed to light is connected to positive terminal and other electrode ‘a’to the negative terminal of the battery.

Conclusion:

The potential across the electrodes is equal to the potential difference reading in the voltmeter.Voltmeter reading will be positive.By reversing the direction of the connection of the variable battery voltmeter can read negative potential.

Answer 14

Ch. 14.1 - In the magnified view of the slits, an arrow is...Ch. 14.1 - For what values of the path length difference...Ch. 14.1 - Suppose that a single change were made to the...Ch. 14.1 - Prob. 2aT Ch. 14.1 - Prob. 2bT Ch. 14.1 - Prob. 2cT Ch. 14.1 - Use trigonometry to show that the path length...Ch. 14.1 - Prob. 3bT Ch. 14.2 - How does the voltmeter reading compare to the...Ch. 14.2 - Prob. 1bT

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