Concept explainers
Interpretation:
The mole fractions of oxygen and nitrogen in the air are to be calculated.
Concept Introduction:
According to Henry’s law, solubility of a gas in a liquid is directly related to the pressure of the gas, and its expression is
Here,
Mole fraction
Answer to Problem 25QP
Solution: 0.677;0.323
Explanation of Solution
Given information: The partial pressures of oxygen and nitrogen are
First, assume that
For
substitute
For
substitute
In one liter of water, moles of
The expression to calculate the mole fraction is
For
substitute
For
Substitute
The mole fractions of
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Chapter 13 Solutions
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