Given the following descriptions of reversible reactions, write a balanced net ionic equation (simplest whole-number coefficients) and the equilibrium constant expression (K) for each.
(a) Liquid acetone (C3H6O) is in equilibrium with its vapor.
(b) Hydrogen gas reduces nitrogen dioxide gas to form ammonia and steam.
(c) Hydrogen sulfide gas (H2S) bubbled into an aqueous solution of lead(ll) ions produces lead sulfide precipitate and hydrogen ions.
(a)
Interpretation:
A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined.
Concept introduction:
For a general equilibrium reaction as follows:
The expression for equilibrium constant of a reaction can be calculated as follows:
Here, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectively
In the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.
Answer to Problem 10QAP
Explanation of Solution
According to the given description, the liquid acetone,
The reaction can be written as follows:
The above reaction is already balanced.
The expression for equilibrium constant will be as follows:
(b)
Interpretation:
A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined.
Concept introduction:
For a general equilibrium reaction as follows:
The expression for equilibrium constant of a reaction can be calculated as follows:
Here, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectively
In the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.
Answer to Problem 10QAP
Explanation of Solution
According to the given description, the reaction of hydrogen gas
The reaction can be written as follows:
To balance the number of oxygen atoms, give coefficient 2 to
Give coefficient 7/2 to
Or,
The expression for equilibrium constant will be as follows:
(c)
Interpretation:
A balanced chemical equation for the given description and the equilibrium constant for the expression should be determined.
Concept introduction:
For a general equilibrium reaction as follows:
The expression for equilibrium constant of a reaction can be calculated as follows:
Here, A and B are reactants with stoichiometric coefficient a and b respectively. Similarly, C and D are products with stoichiometric coefficient c and d respectively
In the expression for equilibrium constant, the species in pure solid and liquid state are not written as equilibrium constant does not depend on them.
Answer to Problem 10QAP
Explanation of Solution
According to the given description, the reaction of hydrogen sulfide gas
Thus, the reaction is as follows:
Give coefficient 2 to
The expression for the equilibrium constant will be:
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Chapter 12 Solutions
Chemistry: Principles and Reactions
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