Foundations of Materials Science and Engineering
Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 10.14, Problem 79AAP
To determine

The amount of weight percent sulfur.

Expert Solution & Answer
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Answer to Problem 79AAP

The amount of weight percent sulfur is 8.49%_.

Explanation of Solution

Show the chemical structure bonding of polybutadiene and polystyrene as:

Foundations of Materials Science and Engineering, Chapter 10.14, Problem 79AAP

Express the weight per cent of sulfur.

    W%S=MS100g+MS×100%     (I)

Here, the molar mass of the sulfur is MS.

Calculate the mass of sulfur at 20%.

    MassofS@20%=(0.20)(NB)(MS)  (II)

Here, the number of mole in butadiene is NB.

Calculate the copolymer total mass.

    Copolymertotalmass=[(7molepolybutadlene×Mpolybutadlene)+(1molepolystyrene×Mpolystyrene)] (III)

Here, the molar mass of the polybutadlene is Mpolybutadlene and the molar mass of the polylstyrene is Mpolystyrene.

Conclusion:

The average molecular mass of the polylstyrene is 105g/mol.

The average molecular mass of the polybutadlene is 54g/mol.

The average molecular mass of the sulfur is 32g/mol.

Substitute 105g/mol for Mpolybutadlene and 54g/mol for Mpolystyrene in the Equation (III).

    Copolymertotalmass=[(7molepolybutadlene×105g/mol)+(1molepolystyrene×54g/mol)]=[378g+105g]=483g

Calculate the fraction of butadlene.

    Fractionofbutadlene=378g483g=0.783

Calculate the number of moles of butadlene using 100 g of copolymer.

    molebutadlene=100g×massofbutadieneMpolystyrene=100g×(0.783)54g/mol=78.3g54g/mol=1.45g

Substitute 1.45 g for mole butadlene and 32g/mol for MS in Equation (II).

    MassofS@20%=(0.20)(1.45mol)(32g/mol)=9.28g

Substitute 9.28 g for MassofS@20% in Equation (I).

    W%S=9.28g100g+9.28g×100%=9.28g109.28g×100%=0.084919×100%=8.49%

Thus, the amount of weight percent sulfur is 8.49%_.

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