(a)
Interpretation:
Osmotic pressure of
Concept introduction:
Osmotic pressure is calculated by below formula.
(1)
Here,
Answer to Problem 37QAP
Osmotic pressure of
Explanation of Solution
Given, Temperature
Convert temperature from Celsius to Kelvin as follows:
Substitute the values of T, M and R in equation (1).
Therefore, osmotic pressure of
(b)
Interpretation:
The osmotic pressure of
Concept introduction:
Expression of molarity of a solution is given below.
Osmotic pressure of the solution is as follows:
Here,
Answer to Problem 37QAP
Osmotic pressure of
Explanation of Solution
Given:
mass of urea
Volume of solution is
The conversion factor is
Use conversion factor to calculate moles of urea
Calculate molarity as follows:
Moles of solute ( n)
Put the above values in equation (2).
Osmotic pressure of the solution as follows:
(3)
Here,
Given, Temperature
Convert temperature from Celsius to Kelvin as follows:
Substitute the values of T, M and R in equation (3).
Therefore, osmotic pressure of
(c)
Interpretation:
The osmotic pressure of
Concept introduction:
Relationship between density, volume and mass is given below.
Answer to Problem 37QAP
Osmotic pressure of
Explanation of Solution
Given:
15.0 % urea by mass.
Density of solution = 1.12 g/mL.
Molar mass of urea
Given, mass
Therefore,
The conversion factor is
Use conversion factor to calculate moles of urea
The relationship between density, volume and mass is given below.
Put above values in (4).
Therefore, volume of the solution is
Calculate molarity as follows:
Moles of solute ( n)
Put the above values in equation (5).
Calculate osmotic pressure of the solution as follows:
Given, Temperature
Convert temperature from Celsius to Kelvin as follows:
Substitute the values of T, M and R in below expression.
Therefore, osmotic pressure of
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Chapter 10 Solutions
Chemistry: Principles and Reactions
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