Pendulum Length (L) = 0.8m gravity (g) 9.81 m/s^2 Small Angle Approximation Period: T=2π g 2pi* square root(0.8/9.81) = 1.79 s^2 L

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter12: Oscillatory Motion
Section: Chapter Questions
Problem 37P
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University Physics 1 - Gravitation & Oscillation

I need help with this problem and an explanation of why its the answer described below:

A Simple Pendulum Lab (Image shown below):

 If the pendulum length were to be quadrupled, by what factor would the period change? Explain your answer without doing any new numerical calculations using data.

Pendulum Length (L) =
0.8m
gravity (g) 9.81 m/s^2
Small Angle Approximation Period:
T=2π
g
2pi* square
root(0.8/9.81)
= 1.79 s^2
L
Transcribed Image Text:Pendulum Length (L) = 0.8m gravity (g) 9.81 m/s^2 Small Angle Approximation Period: T=2π g 2pi* square root(0.8/9.81) = 1.79 s^2 L
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