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You are in a hot air balloon 500meters above the ground. How far is the horizon if the earth radius is 6400km
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- A small light source located 1 mm in front of a 1-m2m2 opening illuminates a wall behind. If the wall is 1 mm behind the opening (2 mm from the light source), the illuminated area covers 4 m2m2. How many square meters are illuminated if the wall is 3 mm from the light source? 5 mm? 10 mm?The diameter of Earth across the equator is 7928 miles. If a mile equals 1.609 km. what is Earths diameter in kilometers? In centimeters?Suppose you need to find the height of a tall building. Standing 15 meters away from the base of the building, you aim a laser pointer at the closest part of the top of the building. You measure that the laser pointer is 7 degreestilted from pointing straight up. The laser pointer is held 2 meters above the ground. How tall is the building?
- The radius of the earth is 6400 Km and the height of a person is 1.7m, how high can you stand to see how far the horizon is from you (going back in degrees after the arc)The mass of the Earth is about 6 x 1021 metric tons, and the mass of the Sun is about 2 x 1027 metric tons. About how many times more is the mass of the sun compared to the mass of the Earth? Put the numbers into Scientific Notation. Do your calculations using the product or quotient rule. Then write your answer as a Standard Number. What is the proper name of the answer?The Earth is about 12,000 km in diameter. It is therefore how many orders of magnitude wider than you are tall? (i.e., the Earth’s diameter is how many times larger than your height (give an order-of-magnitude estimate)?)
- Use Kepler's Law, which states that the square of the time, T, required for a planet to orbit the Sun varies directly with the cube of the mean distance, a, that the planet is from the Sun.Using Earth's time of 1 year and a mean distance of 93 million miles, the equation relating T (in years) and a (in million miles) is 804375T2=a3.Use that relation equation to determine the time required for a planet with mean distance of 206 million miles to orbit the Sun. Round to 2 decimal places. yearsCalculate how many seconds there are in 1.0 Mars year (678 Earth days). Report your answer in scientific notation with the correct number of significant digits.I'm having trouble completing the problem I've attached a picture of below. I was able to find the the Earth's average speed in m/s relative to the sun by doing (2pi*(1.49x10^11))/31536000. But I am struggling to find the average velocity for the same thing over a period of one year in m/s. I was wondering how to calculate that? I've tried doing the (final velocity-initial velocity)/2 but the program doesn't accept my answer when using that approach.
