mass of Cart = 318.89 Kg Trial Final Initial Change of Velocity Velocity Velocity Impulse Vi Vi Δν by JFdt (m/s) (m/s) (m/s) (N.s) 3 -0.4896 0.5347 4 -0.5458 0.5927 Trial Impulse by (Fdt % diff: (N.s) Δρ (kg.m/s) JFdt and Δρ 3 0.3319 4 03695
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- Soogle Chrome plattempt3D252112&cmid%3D1561298&page%3D4 ana sayfası Takvim Nişanlar Tüm dersler Course dashboar The weight on the left is 90 grams and the distance from the center point is 3 units. The distance of the Fr to the center is 2 units. Calculate the Fr values in kg. left side right side 90 grams Fr A) 135 B) 50 C) 0.135 D) 0.713 E) 80 Lütfen birini seçin: O A OB ODIs the answer 550 kg because 55*10= 550And also it is in Newton's so it will be in kilograms so the answer is 550kg if the answer isn't 550kg then what is the answer and how can I get that answer and also explain it to me step by step.mgh = 1 mv ₁ ² 2 Duph FAST 2 m = 1.00 kg 9 = 9.80 m/s² V₁ = 11 m/s ² 2 08.P Solve for hieght (h) MUN TIE
- Seconds uhile it is coun cauming to a shop 42.) A 0.050 kq white ball is thrown hori zontaly tou ord The bartter suings the bat and hits the bally boatter of 12.3 mls o a applying Hhe ball to head back in the an ave rage force f 15.714N to te ball e opposte causing diredtion Causu from the ba Her) at d.70 mis, lossumpg that away drom hatter is the possitive t-diedin, determine the time that the boot and ball wire in Cantact, Report in Mondreths of ansaer your second enter humerical volve7. In the case of intra-muscular injection of a medicament, its mass m(t) in blood changes with time according to the law m(t) = "o (e-kt – e-rt). Here Mo is initial mass of the medicament, k is elimination coefficient and r is absorption coefficient. Calculate (a) the medicament mass in blood 3 hours after injection; (b) Find velocity of the medicament elimination v 3 hours after injection if k = 0,5 (1/hour), r = 2 (1/hour) and Mo = 220 mg. Mor r-kWhile going down a roller coaster 20 m above the ground, a 100kg man is moving at 10 m/s What is the GPE, KE, EPE, and total ME of the man.
- Item 7 Learning Goal: To understand the nature of electric fields and how to draw field lines. Electric field lines are a tool used to visualize electric fields. A field line is drawn beginning at a positive charge and ending at a negative charge. Field lines may also appear from the edge of a picture or disappear at the edge of the picture. Such lines are said to begin or end at infinity. The field lines are directed so that the electric field at any point is tangent to the field line at that point. Figure B D MNM 3 of 4 Part C Which of the following panels (labelled A, B, C, and D) in (Figure 3) shows the correct electric field lines for an electric dipole? O A B Submit Part D In (Figure 3), what is wrong with panel D? (Pick only those statements that apply to panel D.) Check all that apply. Request Answer Field lines cannot cross each other. The field lines should turn sharply as you move from one charge to the other. The field lines should be smooth curves. The field lines should…a uniferm rod AB is weighs SN. what is necessary produced e quilibrium c from A)? 2. cand 5N 3N 50 B 20 I00 cm O cm 2N SN4xgxcoseyxD T×D4×AP128xµ×L h= 0,53 cm Q= 72000 cm³/s D= 20 mm D= 2mm 0= 45° y= 13600N/m3 0= .. .N/m u= 400 kN s/km2 L= 1000 cm AP=. .N/m2 (Pa) 2xgxhxycy-1 V×D9 h= 76 mm Re= 121538 (boyutsuz) Yc= 0,0136 N/cm3 V= 12,01 km/h 9- 46,8 cm?/s V= 7,9.10-' m/s D=.... .m g= 9,81 m/s? Y=.. .kN/m³ 8×LxQ2xfr2×g×D5 L= 5 km f= 0,01277 (boyutsuz) g= 9,81 m/s? Q= 1440000 dm³/h D= 442,1 mm h=........m
- Convert and put the following in standard form30 km to m35 cm to m220 Mg to g0.03 mm to m29 ns to s50 Gw to wto mمملكة 25° vzconst m= 5 ка M Find coof of feination mass is moun if mass with constant velocity Мич movingA differential equation describing the velocity v of a mass m in fall subject to an air resistance proportional to the instantaneous speed is m dv/dt=mg-kv, where k is a positive proportionality constant. a) Solve the equation, subject to the initial condition v(0) = v0 b) Calculate the limiting speed of the mass. c) If the distance s is related to the speed by ds/dt = v, derive an equationexplicit for s, if it is also known that s(0) = s0 topic:ORDINARY DIFFERENTIAL EQUATIONS