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1)Robert E. (1917–1989) discovered two planets. he estimated their masses to be m and M and found that the ratio of their masses, M/m = 36. The distance between the planets is L. The point P, is between the planets and the distance between m and P is x. The gravitational forces on an object at P, due to M and m, are equal in magnitude.
A) What is the value of x?
B) If you replace the two planets (now x is the distance between M and P), what would be the new value of the x?
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- pps52 please dont copy existing answers or i will dislike your answer thanksHuhujujuuu plzA signal from of PLDT-Fibr travels through its optic cable at the speed of (2x108 m/s).a.) How long will it take for the signal to travel from our house to LJ’s house which has a30.35 km distance b.) What length in inches of the optic cable represents 0.75 ms(millisecond)?
- A2 i cant seem to understand this from our lecture, i would also love an explanation on how to understand these for the future !Commonly, medical digital radiology ultrasound studies consist of about 25 imagesextracted from a full-motion ultrasound examination. Each image consists of 512 by512 pixels, each with 8 b of intensity information.a. How many bits are there in the 25 images?b. Ideally, however, doctors would like to use 512 * 512 8-bit frames at 30 fps(frames per second). Ignoring possible compression and overhead factors, what isthe minimum channel capacity required to sustain this full-motion ultrasound?c. Suppose each full-motion study consists of 25 s of frames. How many bytes ofstorage would be needed to store a single study in uncompressed form?Determine the Dynamic range for a 10-bit sign-magnitude PCM code.
- T14d please help me with my reviewer, I can’t get the value for the step 2, also kindly give me a detail solution so that I can’t I understand it thank youSolve plzzzz with correctCompute ID for the following cases, You can use Kp=Kn= 20U 3. VGS= -2V, VDS = 1V, VT= -1V 4. VGS= 2V, VDS = 1V, VT= 3V 5. VGS= 0V, VDS = 1V, VT= -1V 6. VSG= 5V, VSD = 1V, VTP= -3V 7. VSG= -2V, VSD = 1V, VTP= -3V 8. VSG= 3V, VSD = 5V, VTP= 0V 9. VSG= 4V, VSD = 4V, VTP= -1V 10. VSG= 2V, VSD = 1V, VTP= -3V
- Find out the correct relation from the following. a) 1 Wb = 1 G cm b) 1 Wb = 1 Tm c) 1 Wb = 1 G cm2 d) 1 Wb = 108 MaxwellExample 16.9. Prove that Jgx) = 3- sin x 3 cos x TEX640 a session.masteringphysics.com/myct/itemView?assiqnmentProblemID=1363028568zoffset-next MasteringPhysics: HW6 Apps (1) ইমাম মাহদী কবে... YouTube to MP3 Co... phone cover for mo... 4Online Services Fo... AGARWAL-PHY-166 muhammad CHW6 Item 2 2 of 13 A child in a boat throws a 5.20-kg package out horizontally with a speed of 10.0 m/s. The mass of the child is 24.6 kg and the mass of the boat is 34.6 kg. (Figure 1) Part A Calculate the velocity of the boat immediately after, assuming it was initially at rest. Figure Express your answer to three significant figures and include the appropriate units. Enter positive value if the direction of the velocity is in the direction of the velocity of the box and negative value if the direction of the velocity is in the direction opposite to the velocity of the box. 1 of 1 НА Value Units v = 10.0 m/s Submit Request Answer Provide Feedback Ne 5:18 F 4/14/2 Type here to search hp ||