How would I figure this out using a punnett square? Next, you perform a cross of two heterozygous, red-eyed flies. They have 100 offspring. How many of these offspring do you predict will have red eyes? Show your work using a Punnett square. [Use letters R and r to designate the alleles].
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How would I figure this out using a punnett square?
Next, you perform a cross of two heterozygous, red-eyed flies. They have 100 offspring. How many of these offspring do you predict will have red eyes? Show your work using a Punnett square. [Use letters R and r to designate the alleles].
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- A friend tells you that her biological father has an inherited disorder determined by a dominant allele but neither your friend nor her three siblings are affected. Is this possible? If not, why not? If so, explain how it is possible. For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). BIUS Paragraph Arial 14px A V x² X, ABC 田 田 | 国田用田 Ť {;} III !!! +)Fruit fly body color is wild type (meaning normal) Gray = B+ and black = b Fruit fly wing type is wild type normal wings = vg+ and vg = vestigial A fly which was heterozygous for both traits was crossed with a fly that was recessive for both traits. Write the genotype and phenotype that would be expected from this cross. Write the genotype and phenotype percentages that would be expected from this cross.you perform a cross of two heterozygous, red-eyed flies. They have 100 offspring. How many of these offspring do you predict will have red eyes? Show your work using a Punnett square. [Use letters R and r to designate the alleles]
- Red color (R) allele is dominant over blue color (r) for carnations (a type of flower). You will cross a heterozygous red carnation with a blue carnation. Show all your work filling out the required parts of the diagram. Then, select the correct statement below. (Please complete the Punnett Square correctly.)& (Picture below) 1. 75% red - 25% blue 75% heterozygous - 25% homozygous 2. 75% red - 25% blue 75% heterozygous - 25% homozygous 3. 50% red - 50% blue 50% heterozygous - 50% homozygous 4. 25% red - 75% blue 25% heterozygous - 75% homozygous Thank you!pt pt PT PPTt purple tall PpTt purple tall Pt Pptt purple white Pptt purple white Using any two plants resulting from your test cross (even two of the same genotypes if you would prefer), perform a second cross. Provide a Punnett square demonstrating this dihybrid cross.What are the ratios for each genotype in the resulting offspring? What are the ratios for each phenotype? Your answer should clearly indicate the genotype and phenotype each portion of the ratio is referring toProduce a Punnett square to illustrate the dihybrid cross described below (NOTE: It is the same story as in question 9, above so you may use the square that you produced in answer to question 9 to answer this question, you do not need to draw it twice). use it to fill in the blanks in the answer text below. NOTE: please type in whole numbers only, no symbols, no letters, no spaces. There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the…
- Produce a Punnett square to illustrate the dihybrid cross described below (NOTE: It is the same story as in question 9, above so you may use the square that you produced in answer to question 9 to answer this question, you do not need to draw it twice). use it to fill in the blanks in the answer text below. NOTE: please type in whole numbers only, no symbols, no letters, no spaces. There are two common alleles for the TAS2R38 gene on Chromosome 7. This gene encodes a seven-transmembrane G-protein coupled receptor. This receptor controls the ability to taste glucosinolates. Phenylthiocarbamide (PTC) is a synthetic glucosinolate. The recessive TAS2R38 allele produces a non-functional receptor. The father in this dihybrid cross is heterozygous for these alleles, meaning that he can taste PTC. The mother is homozygous recessive, meaning that she cannot taste PTC The father has X-Linked Protoporphyria which means that he is very sensitive to sunlight exposure, he is hemizygous for the…In this pedigree chart, what is the genotype of individual III-1? (It's circled in blue.)The table below shows the progeny of a test cross of a heterozygote (JjBbRr). Each row shows the number of progeny that inherited each combination of alleles from the heterozygous parent. You've already determined the gene order (B is in the middle) and labeled each type of progeny. Using this information, what is the recombination frequency between J and B? Alleles: Type: Count: J B R Parental 132 j b r Parental 135 J b R DCO 15 j B r DCO 11 J b r SCO (J-B) 59 j B R SCO (J-B) 55 J B r SCO (B-R) 38 j b R SCO (B-R) 40 Group of answer choices 0.214 0.235 0.289 the correct answer is not available. 0.503 0.14
- type P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONSSEATWORK Symbols (for pea plant traits): • T: Tall t: short Analyze the following problems. Determine the possible genotypes, genotypic ratio, phenotypes, and phenotypic ratio from the genetic cross. Show your solution through a Punnett square. Use the symbols provided. • R: Round seeds r: wrinkled seeds • Y: Yellow seeds y: green seeds • P: Purple flower p: white flower 1) Cross a homozygous dominant tall and homozygous round seed pea plant with a heterozygous tall and heterozygous round seed pea plant. 2) Cross a pea plant that is heterozygous for purple flowers and homozygous dominant for yellow seeds with a pea plant that is heterozygous for purple flowers and homozygous recessive for green seeds. 3) Cross a pea plant that is short and has green seeds with a pea plant that is heterozygous tall and has heterozygous yellow seeds.We have crossed true-breeding flies today. Wild type to mutant. Their phenotypes were wt and vg se. (Let’s not worry about males and females for now, just assume both genes are autosomal, which is normal in a Mendelian experiment). The results of a cross are phenotypes. I will be asking you for numbers or a ratio of phenotype numbers you expect to see in the offspring from this cross. To answer this, you’ll need to start with the genotypes of parents, then write their gametes, then write the offspring genotypes, then get the phenotypes based on them. Predict the results of this cross: In case both mutations are recessive; In case both mutations are dominant; In case vestigial wings are recessive and the sepia eyes are dominant.