enzyme-inhibitor complex requires 450 kJ.mol-1 to dissociate and that it displays kinetics somehow similar to non-competitive inhibition, this enzyme is good to use to inhibit toxanthine oxidase in the case of hyperuricemia and gout?
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enzyme-inhibitor complex requires 450 kJ.mol-1 to dissociate and that it displays kinetics somehow similar to non-competitive inhibition, this enzyme is good to use to inhibit toxanthine oxidase in the case of hyperuricemia and gout?
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- Distinguishing the Mechanisms of Class I and Class I Aldolases Fructose bisphosphate aldolase in animal muscle is a class 1 aldolase, which forms a Schiff base intermediate between substrate (for example. fructose-1, 6-bisphosphate or dihydroxyacetone phosphate) and a lysine at the active site (see Figure I8.12). The chemical evidence for this intermediate conies from studies with aldolase and the reducing agent sodium borohydride, NaBH4. Incubation of the enzyme with dihydroxyacetone phosphate and NaBH4 inactivates the enzyme. Interestingly, no inactivation is observed if NabH4 is added to the enzyme in the absence of substrate. Write a mechanism that explains these observations and provides evidence for the formation of a Schiff base intermediate in the aldolase reaction.enzyme-inhibitor complex requires 450 kJ.mol-1 to dissociate and that it displays kinetics somehow similar to non-competitive inhibition, does this is inhibitor good to use to inhibit toxanthine oxidase in the case of hyperuricemia and gout?The table below shows the purification of liver lactate dehydrogenase. Purification Table of liver LDH Step Crude Extract Ammonium Sulfate DEAE-Sephadex 5'AMP-Sepharose Volume (mL) 200 100 112 40 LDH activity (Units/mL) (mg/mL) [Protein] 47.0 50.00 90.0 63.00 51.0 1.50 137.0/ 0.4 Calculate the LDH yield for the ammonium sulfate step. Provide answer to one decimal only. Show Transcribed Text this is biochemistry and the topic is protein purification could you pleaae show me the full workings even the workings for the comversions
- Calculcate Kcat for PNP substrate for both enzyme concentrations. enzyme volume: 20 ul Bovine Intensince Alkaline phosphatase molecular weight: 140,000 Bovine intenstine Alkaline phosphatase activity: 300 units/ml and 14 units/mg extinction coefficient PNP: 18.5 abs (mM-1 cm-1) Vmax: 0.332 moles/sec a) enzyme 1 concentration: undiluted b) enzyme 2 concentration: 1:1 dilutionWhat is the catalytic efficiency of Catalase ? Table. The values of KM and kcat for some Enzymes and Substrates Enzyme Carbonic anhydrase Substrate CO2 HCO3 KM (M) 1.2 x 10-2 2.6 x 10-2 Kcat (s-1) 1.0 x 106 4.0 x 105 Catalase H2O2 2.5 x 10-2 1.0 x 107 Urease Urea 2.5 x 10-2 4.0 x 105 O A. 4 x 108 M-s-1 O B. 4 x 108 M-1.s-1 OC25x 10-9 M-s1 D. 2.5 x 102 M-1.s-1 OE 1.0 x 107 s1The lipase substrate emulsion contains 0.500 mg of olive oil per 3 mL Also, the molar mass of the olive oil is 885 g/mol. If all of the olive oil in a 3 mL reaction is "digested" by pancreatic lipase in a reaction, how many molecules of olive oil have been degraded?
- at what substrate concentration is v= 5.0 mM s^-1 for the enzyme catalyzed hydrolysis of trehalose?Normal carbonic anhydrase has zinc at its active site . Suggest a structural reason why carbonicanhydrase synthesized with Ni²⁺, Fe²⁺, or Mn²⁺ in place of Zn²⁺ gives an enzyme with less catalytic efficiency.How to calculate the percent inhibition of xanthine oxidase enzyme inhibition with a blank absorbance value lower than the sample absorbance? Can the formula (Asample-A blank)/Asample ) x 100% be used? Thank you if you are willing to explain in detail Thank you.
- For the following aspartase reaction in the presence of the inhibitor hydroxymethylaspartate, determine Km and whether the inhibition is competitive or noncompetitive. You have to plot thegraph on the graph paper and also by using excel.[S] V, No Inhibitor V, Inhibitor Present(molarity) (arbitrary units) (same arbitrary units) 1 x 10-4 0.026 0.0105 x 10-4 0.092 0.0401.5 x 10-3 0.136 0.0862.5 x 10-3 0.150 0.1205 x 10-3 0.165 0.142The muscle isozyme of lactate dehydrogenase is inhibited by lactate. Steady state kinetic analysis yielded the following data, with lactate either absent or present at a fixed concentration.Glucosidase I catalyzes hydrolysis of specific glucosidase I is a synthetic trisaccharide, glucose-al-2- glucose-al-3-glucose-a-O(CH₂) #COOCH3. Kinetic measurements oligosaccharides containing glucose. obtained using this trisaccharide as substrate in the deoxynorjirimycin at concentrations of 50 μM (), 100 μM absence (x-x) and presence of the inhibitor 1- A) were used to prepare the (-), and 200 μM (4 Lineweaver-Burk plot below: b) Page 3 12) 7. a) V/V (nmol/hr)-1 1.S 1.0- 0.5 1/Trisaccharide (mM)-! Estimate the values for Vmax and KM for the trisaccharide substrate in the absence of the inhibitor. 0.0 -1.0 0.0 One substrate for 1.0 2.0 Determine whether inhibition by 1-deoxynorjirimycin is competitive, non-competitive or neither.