A brick of mass 4 kg hangs from the end of a spring. When the brick is at rest, the spring is stretched by 5 cm. The spring is then stretched an additional 4 cm and released. Assume there is no air resistance. Note that the acceleration due to gravity, g, is g=980 cm/s. Set up a differential equation with initial conditions describing the motion and solve it for the displacement s(t) of the mass from its equilibrium position (with the spring stretched 5 cm). s(t)=?

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter4: The Laws Of Motion
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A brick of mass 4 kg hangs from the end of a spring. When the brick is at rest, the spring is stretched by 5 cm. The spring is then stretched an additional 4 cm and released. Assume there is no air resistance. Note that the acceleration due to gravity, g, is g=980 cm/s.

Set up a differential equation with initial conditions describing the motion and solve it for the displacement s(t) of the mass from its equilibrium position (with the spring stretched 5 cm).

s(t)=?

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Expert Solution
Step 1: Given data

Given:

The mass of the hanging brick: space m equals space 4 space kg

Displacement from the equilibrium position: x space equals space 5 space cm left parenthesis 0.05 space straight m right parenthesis

The additional displacement of the spring: x apostrophe space equals space 4 space cm left parenthesis 0.04 space straight m right parenthesis

The acceleration due to gravity: g equals 9.80 space straight m divided by straight s squared



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