A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring feet. The ball is started in motion from the equilibrium position with a downward velocity of 7 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in feet per second). Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.) Take as the gravitational acceleration 32 feet per second per second. y =

icon
Related questions
Question
A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring feet. The ball is started in motion from the
equilibrium position with a downward velocity of 7 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its
velocity (in feet per second) .
Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.)
Take as the gravitational acceleration 32 feet per second per second.
y =
Transcribed Image Text:A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring feet. The ball is started in motion from the equilibrium position with a downward velocity of 7 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in feet per second) . Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.) Take as the gravitational acceleration 32 feet per second per second. y =
A brick of mass 2 kg hangs from the end of a spring. When the brick is at rest, the spring is stretched by 3 cm. The spring is then stretched an
additional 4 cm and released. Assume there is no air resistance. Note that the acceleration due to gravity, g, is g = 980 cm/s².
Set up a differential equation with initial conditions describing the motion and solve it for the displacement s(t) of the mass from its equilibrium position
(with the spring stretched 3 cm).
s(t) =
cm
(Note that your answer should measure t in seconds and s in centimeters.)
Transcribed Image Text:A brick of mass 2 kg hangs from the end of a spring. When the brick is at rest, the spring is stretched by 3 cm. The spring is then stretched an additional 4 cm and released. Assume there is no air resistance. Note that the acceleration due to gravity, g, is g = 980 cm/s². Set up a differential equation with initial conditions describing the motion and solve it for the displacement s(t) of the mass from its equilibrium position (with the spring stretched 3 cm). s(t) = cm (Note that your answer should measure t in seconds and s in centimeters.)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 10 steps

Blurred answer