7. Match the anticodons with the corresponding codons. Consider the laws of super wobble. Codon (5' to 3 anticodon (5' to 3') a. AAU i. GUU b. AAC ii. GGA C. UCU iii. UGC d. UCC iv. AUU e. GCG v. AGA f. GCA vi. CGC I
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Molecular Biology
Step by step
Solved in 2 steps
- 1. TRUE OR FALSE a) The genetic code in unambigous that means many codons can code for the same amino acids. b) There are no aminoacyl-tRNAs that will go to the A site of the ribosome when UGA is the codon.Which of these molecules has multiple partial charges and thus is most soluble in water? B H HHH HHH ABCD or E CH H CHOH D CH OH A cell is specialized in producing oil and steroid hormone. Which structure would be found in large r cell? O vacuoles O peroxisome O rough endoplasmic reticulum O smooth endoplasmic reticulum The oxygen released from photosynthesis results from: Reduction of NADP* to NADPH Chemiosmosis Oxidation of water PhotophosphorylationRefer to the Table of the Genetic Code and match the type of mutation to the following codon changes CUU --> CCU 1. Conservative GAA --> GAU 2. Missense UCA --> UAA 3. Nonsense 4. Synonymous CCU --> CCG > >
- 26. What is the start codon and the corresponding amino acid for which it codes? FIISI DASO U G UUU UUC UUA U CUU CUC CUA CUG AUA AUG GUU GUC GUA GUG PHE AUU AUC ILE GAU-ASP LEU MET or START LEU GUA-VAL AGU-SER VAL AUG- MET UCU UCC UCA UCG C CCUT CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Second base SER PRO THR ALA UAU UAC UAA UAG CAU CAC CAA CAG A GAUT GAC GAA 1 GAGJ STOP UGU TYR CYS UGC UGA STOP UGG TRP G HIS GLN AAC ASN AAA AAG J LYS ASP GLU G CGU CGC CGA CGGJ AGU AGC. AGA AGG GGU GGC GGA GGG >ARG SER ARG UCAG GLY UCAG UCAG UCAG THILD DASO REQUIRED E ce_______ are removed from new mRNAs. a. Introns c. Poly-A tails b. Exons d. Amino acids2. Transcribe the following gene sequence to the appropriate MRNA codons: TCA TTT CCA CAG ACA * AGU AAA GGU GUc UGU 3. Translate the mRNA codons (i.e. your answer to question 2) into the appropriate amino acids using the following Universal Genetic Code Chart. * Universal Genetic Code Chart Messenger RNA Codons and the Amino Acids for Which They Code SECOND BASE A UCU UAU UGU UUU UUC UUA PHE TYR CYS UCC UCA UAC UGC SER UAA UGA STOP LEU STOP UUG UGG} TRP UCG UAG CUU CCU CAU CGU HIS CUC CCC CAC CGC LEU PRO ARG CCA CCG CUA CAA CGA GLN CUG CAG CG AUU AUC ACU AAU AGU AGC AGA ASN SER ILE ACC AAC THR AAA AAGS ACA AUA AUG MET or START LYS ARG ACG AGG S GCU GCC GUU GAU GGU ASP GUC GAC GGC VAL ALA GLY GUA GCA GCG GAA GGA GGG GLU GUG GAG トエーCロ ASE A, L-RST BASE
- Give the complementary codons, anticodons, and amino acids for the following: - ATG - CCA-AGG-GCT - ACT Code: TAC-TCG-CGC-ACC-GTA-TGC Give the complementary code, anticodons, and amino acids for the following: Codon: AUG - UCA - UCU - CGU - UAC - CCU - GCC-ACU-GCA - CUG - UAG Give the complementary code, codons, and amino acids for the following: Anticodon : UAC – CUA – GAC – AUG – GGG – CAU – UGG – CCA – GCA – AUU Complete the following tables: CODE: T-A-C A-T-G C-C-G T-G-G A-A-T C-G-C A-T-T CODON: ANTICODON: AMINO ACID: CODE: CODON: ANTICODON: U-A-C A-U-G U-U-C C-G-A AMINO ACID: CODE: CODON: A-U-G ANTICODON AMINO ACID: T-T-A C-C-U A-U-C A-U-C C-C-U A-C-U C-U-G T-A-C U-A-G1. Considering the following nucleotide sequence in an mRNA molecule: 5’ AUG UUA CGU AAU GCU GUC GAA UCU AUU UGC UUU ACA UAA 3' a) Write the sequence of the DNA template (antisense) strand from which the mRNA was synthesized. b) Write the sequence of the DNA coding (sense or informational) strand complementary to the template strand. c) Write the sequence of tRNA anticodon that corresponds to the given mRNA molecule. d) Write the amino acid sequence of the peptide synthesized from the given mRNA nucleotide sequence. e) Draw the structure of the pertide fragment made up of the first five (5) amino acids in the given polypeptide.AAG ATA CAG GCT CGG TAA For the DNA sequence shown above, identify the following: a. mRNA codons b. tRAN anticodons c. amino acids
- 6. Similar to the class notes (Intro to Genetics), a segment of DNA (shown below) contains a promoter segment (the first 9 base pairs), a ribosome binding segment (the next 6 base pairs), and a segment that codes for protein synthesis which is started by the rest of the base pairs. ACTCCATTGAACCATTTCTATGATCCGCTAACG-... TGAGGTAACTTGGTAAAGATACTAGGCGATTGC-... A. When the DNA is induced to be copied to mRNA, the top strand is coding, meaning that the mRNA makes an identical copy of the lower strand (replacing T with U) The mRNA copy starts with the ribosome binding sequence. What is the sequence of the mRNA that will go to the ribosomes? B. What are the first 6 amino acids of the protein that are coded for by the mRNA? C. What would the amino acid sequence be if... i. a transition mutation occurred on the final G in the mRNA? ii. all of the G & C bases in the protein synthesis portion had transition mutations? iii. a point deletion mutation occurred in the ATA sequence (in the lower strand…Given Sequence: 3’ – TACGGACTGATAGGCCCGCGCATC-5’ a.Complementary Strand: b. Direct Transcript: c. Transcript for Translation: d.Translated Amino Acid Sequence:1. The following is the DNA sequence of a gene: 3' TACTAACTTAGCCTCGCATC S' a. What amino acids are coded by this sequence? b. An adenine is inserted in this strand after the first guanine from the left. The resulting polypeptide is six amino acids long. Where is the newly produced nonsense codon located? What is the amino acid sequence in the fragment?