Volume

quantification: measure by type vs. holistic measure 2.3.2.1 Flexibility measurement: measure by type 1. Volume flexibility Descriptive measure of volume flexibility can be the lower and upper bound of capacity for range dimension and time/cost of capacity adjustment for response perspective. But economic metrics are most commonly used in literature, since many researchers define volume flexibility as the ability to profitably produce at different levels. Stigler(1939) considered a plant to be

Purpose: The lab was performed for the purpose of calculating the density of each type of object and determining if calculating the volume, and therefore the density, of two cubes can be more effectively done with a ruler (through the direct method) or by water displacement. Materials: 1 Scale 1 Rock 2 Corks 2 Aluminum Cubes 4 Paper clips 2 Marbles 1 50 mL graduated cylinder 1 25 mL graduated cylinder 1 Calculator 1 Ruler Procedure: 1. Weigh and record the mass of each pair of objects (only use

Density is the measurement of an object that has a relative mass and is divided by a specific volume. Mass is the amount of matter an object possesses. Volume is the amount of space of an object occupies (solid, liquid or gas.) In chemistry the term density can be described as a physical and intensive property of matter. The term intensive property means, it is independent on the size and amount of a substance. Many chemist compare different types of densities of elements and substance with water

small volumes. A micropipette is standard laboratory equipment used to measure and dispense a specific volume of liquid (#5 buffalostate.edu). This is a very helpful tool that we need to master and able to use in a biochemistry lab. The purpose of this lab exercise is learning how to use a micropipette to find the density of different liquids, and be able to identify an unknown liquid using density. Also, learn how to evaluate the experimental accuracy, precise, and error of small volumes used in

variable is the height of the water and the density of the water. Background Research How do objects float on water? The density and buoyancy are properties of matter that determine how objects float on water. Density shows the amount of mass in the volume of an object. For example, the density of water is one gram per cubic centimeter. It is a property that the quantity or shape does not affect the density of the material. This means that

accurate and precise measurements while utilizing the correct volumetric containers that are used to quantify data. That way, all information that is collected can be trusted and accurately reflects the facts of the investigation. When measuring the volume of aqueous solutions, it is imperative to acknowledge the accuracy, precision, and percent error of the measurements. Accuracy is how close the results are to the actual accepted measurement, also known as the “true” value. Precision is how close

would be calculated to determine whether the objects are made of the same material. The objects are all different colors, sizes, textures and shapes. In order to find density, the mass and volume would need to be calculated. In order to calculate the density of an object two things must be calculated the mass and volume of the object.

Fermentation is the anaerobic process by which glucose, or other sugars are catabolized by microorganisms without an electron transport chain, like yeast (Campbell, 2004). In experiment one the yeast and glucose acted as reactants, with the yeast breaking down the glucose, producing the products CO2 and ethanol. The overall reaction for the alcoholic fermentation that took place can be represented as 2 pyruvate + 2NADH-> 2NAD+ +2CO2 + 2 ethanol (Campbell, 2004). This biological process allows cells

Gummy Bear Lab 1. The volume of the gummy bear increased when we put it in water for twenty four hours. Originally, the volume of the bear was 1.75cm3. After the bear was in the water for twenty four hours, its volume increased to 10.5cm3. So, to find the change in volume, you subtract the new amount from the original. 10.5cm3-1.75cm3= 8.75cm3. The change in volume is 8.75cm3. 2. If we used water displacement to find the volume of the gummy bear instead of the formula (l*w*h) the results would

a) the balance A will read more than 2 kg b) the balance B will read more than 5 kg c) the balance A will read less than 2 kg and B will read more than 5 kg d) the balances A and B will read 2 kg and 5 kg respectively 18. Equal volumes of liquid are poured in the three vessels A, B and C (h1 < h2 < h3). All the vessels have same base area. Select the correct alternatives. [pic] a) The force on the base will be maximum in vessel A. b) The force on the base will be maximum